Circular Motion 1
Projectile Motion 1
Motion in a Gravitational Field
Projectile Motion 2
Random
100

If 5 revolutions take 356 seconds. 

Give the PERIOD for one revolution.

PERIOD (T) = 71.2 seconds
100

The y velocity at a peak height is 

0 m/s

100

Define escape velocity

The speed required for an object to overcome the gravitational pull of a planet.

100

There is _________ acceleration along the horizontal x axis.

zero acceleration

100

A planet's orbital period is proportional to the size of its orbit.

a) Kepler's First Law

b) Kepler's Second Law

c) Kepler's Third Law

A planet's orbital period is proportional to the size of its orbit.

Kepler's Second Law


200

What is the formula for centripetal acceleration

ac = v2/ r
200

Calculate the RANGE for a cannon which covers a peak height in 6 seconds. The cannon has an initial x  velocity of 10 m/s.

s = V x t

s = 10 x 2(6)

s = 120m


200

The imaginary line joining a planet and the Sun sweeps equal areas of space during equal time intervals as the planet orbits.

Kepler's Second Law

200

Find the final Y velocity for a cannon as it strikes the ground. Note the initial Y velocity 0 and the time taken to strike the ground from the peak is 3 seconds.

Vy = Uy + at

Vy = Uy + at

Vy = 0 + 9.8(3)

Vy = 29.4 m/s

200

A skater comes off a ramp at an initial x velocity of 10m/s. 

The time taken to reach the peak was 4 seconds. 

CALCULATE the RANGE or HORIZONTAL DISPLACEMENT for the skater.

s = V x t


s = 10 x 2(4)

s = 80m

300

Give the formula for centripetal force. 


F= mv2 / r

300

Calculate the initial X and Y velocity for a skater who moves off a ramp at an angle of 30o

The initial velocity of the skater is 15 m/s.

X initial velocity = 15 Cos 30  = 13 m/s

Y initial velocity = 15 Sin 30 = 7.5 m/s

300

The squares of the orbital periods of the planets are directly proportional to the cubes of the semi-major axes of their orbits.

a) Keplers First Law

b) Keplers Second Law

c) Keplers Third Law

Keplers Third Law

300

A skater comes off a ramp at an initial x velocity of 11m/s. 

The time taken to reach the peak was 2 seconds. 

CALCULATE the RANGE or HORIZONTAL DISPLACEMENT for the skater.

s = V x t

s = 11 x 2(2)

s = 44m

300

An electric bike is moving around a circular track at a speed of 20 km/hr. 

The track has a radius of 12m. 

CALCULATE the acceleration.

a = v2/r

a = 202/12

a = 0.46 m/s/s

400

Calculate the CENTRIPETAL FORCE for a washing machine with a radius of 0.5 m. 

A 1.2kg bag is placed in the machine and moves at a velocity of 2m/s. 

Fc = mv/ r


Fc = mv/ r

Fc = (1.2)(2)2 / 0.5

Fc = 9.6 N

400

A skater comes off a ramp at an initial x velocity of 12m/s. 

The time taken to reach the peak was 2 seconds. 

CALCULATE the RANGE or HORIZONTAL DISPLACEMENT for the skater.

s = V x t

s = 12 x 2(2)

s = 48m

400

Which TWO formulas are required to derive the ESCAPE VELOCITY formula. 


v = (square root) 2GM/r 

Kinetic energy formula

1/2 mv2

Potential energy formula

GMm/r

400

Find the VELOCITY for a cannon as it hits the ground. 

The X velocity is 10 m/s 

The Y velocity is 15 m/s

V = square root (102 + 152)

V = square root (325)

V = 18 m/s

400

Calculate the ANGULAR VELOCITY for a wheel. 

The wheel has a radius of 20 m and completes one revolution in 5 seconds. 

V = 2 x (pi) x r / T


V = 2 x (3.14) x 20 / 5

V = 25.13 m/s

500

An electric bike is moving around a circular track at a speed of 40 km/hr. 

The track has a radius of 10m. 

CALCULATE the acceleration.

a = v2/r

a = v2/r

a = 112/10

a = 12.3 m/s/s 

500

The initial Y velocity was 7.5 m/s. 

The final velocity is 0 at the peak.

CALCULATE  the TIME TAKEN to reach a peak.


v = u + at

v = u + at

t = v-u/a

t = -7.5 /9.8

t = 0.77 seconds

500

R/T2    =    R3 /T2

Use the formula to find the PERIOD for PLANET B

20003km / 0.52 Earth days         =  30003 km/T2

T = (square root) 30003 (0.5)2 / 20003

 

    

T = 5.13 x 10^-3

500

If the average time to fall from a ride is 5 seconds. Calculate height of the ride.

s= ut +1/2at2


s= ut +1/2at2

s= 0 + 4.9 x 52

s=  122.5 m

500

The initial Y velocity was 15 m/s. 

The final velocity is 0 at the peak.

CALCULATE  the TIME TAKEN to reach a peak.


v = u + at

v = u + at

t = v-u/a

t = -15 /9.8

t =  1.53 seconds

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