Periodic Trends / Electron Configurations
Organic Chemistry
100

What is the electron configuration of cromium

1s2 2s2 2p6 3s2 3p6 4s1 3d5

100
Name this molecule: NH2CH2CH2CHO

3-amino propanal

200

Define first ionisation energy

The minimum amount of energy required to remove one valence electron from every atom in a mole of atoms in their gaseous state

200

Identify the chiral carbon and explain why it is chiral
CH3CH(OH)CH2CH3

Carbon 2. It has 4 different groups attached (-CH3, -H, -OH, -CH2CH3)

300

Rank Al, B, F and Na from the smallest to the largest electronegativity

Na < Al < B , F

300

Give the products of the hydrolysis of N-ethyl ethanamide CH3-CH2-NH-CO-CH3 in acidic and basic conditions

Acids: CH3-CH2-NH3+ and CH3-COOH

Basic: CH3-CH2-NH2 and CH3-COO-

400

Explain why atomic radius decreased from left to right across Period 2

Nuclear charge increases as the number of protons increase, while electrons are added to the same energy level. Shielding dose not increase so the strong nuclear charge results in a strong electrostatic force pulling electrons closer to the nucleus, decreasing atomic radius

400

An unknown organic molecule produces these observation 

- It reacts with Fehling's solution forming a brick-red precipitate

- It reacts with sodium carbonate producing a gas

- It reacts rapidly with Lucas' Reagent turning cloudy 

Identify the functional groups responsible for the observation

Reacts with Fehling's solution = Aldehyde

Reacts with sodium carbonate = Carboxylic Acid

Reacts rapidly with Lucas' Reagent = 3o Alcohol

500

Explain why Al has a lower first ionisation energy than Mg, even though it is further right in period 3

The first electron removed from Al is a 3p electron, whereas the first electron removed from Mg is a 3s electron. The 3p electron is higher in energy, further from the nucleus and more shielded from the. It is therefore easier to remove, giving Al a lower first ionisation energy than Mg.

500
Give the steps to convert propene into propanoyl chloride

CH3-CH=CH2 + HBr --> CH3-CH2-CH2-Br

CH3-CH2-CH2-Br + KOH(aq) --> CH3-CH2-CH2-OH

CH3-CH2-CH2-OH + Cr2O72-/H+ --> CH3-CH2-COOH

CH3-CH2-COOH + SOCl2 --> CH3-CH2-COCl

M
e
n
u