Solving Radical Equations
√(6k+90) = k + 3
K = 9
There are 5 people that initially complete a survey. If the amount of people completing surveys doubles per day, how many people will have taken the survey after 15 days?
163,840 people
Simplify:
(x^2-x-2)/(2x^2-5x+2) times (2x^2+5x-3)/(x^2-x-12)
(x+1)/(x-4)
You invested $10,000 at 6% interest compounded quarterly for 4 years. What was your total return for the investment?
A=$12,689.86
52x = 20
x=.93
√(3n+25) = √(n+9)
n = -8
Jason invested $3000 into Bank of America. The investment is set to increase at the rate of 8% yearly. How long will it take for Jason's investment to triple (rounded to the nearest whole number)?
14 years
3y/(y^2-25) minus 8/(y-5)
(-5y-40)/(y+5)(y-5)
You borrowed $50,000 for 6 years at 13.3% interested compounded semi-annually. How much will you have to pay back?
A=$108,268.10
4x-8=2
x=8.5
24= 8√(-3-3v)
v=-4
Amy bought a diamond ring for $6000. If the value of the ring increases at a constant rate of 3.38% per year, how much will the ring be worth in twenty-one years?
A = $12,059.20
5x/(x^2-x-6) plus 4/(x^2+4x+4)
(5x^2+14x-12)/(x-3)(x+2)(x+2)
You gave your friend a loan of $20,000 at 4% compounded continuously for 2.5 years. How much do you expect to receive back?
A=$22,103.42
log2163
12
√(32-7n) = n-6
no solution
You bought a car for $26,000. If its value depreciates by 12% every year, how much will it be worth after 5 years?
$13721.03
Solve:
x/12 + 1/4x = -1/3
x=-1 & x=-3
Jennifer invested $10,000 into a bank. Her investment received 6% interest compounded continuously. She now has $13,498.59. How many years have passed (expressed as a whole number)?
5 years
simplify log327-3
-9
-8 + √(39b+3) =1
b=2
The value of a car decreases by 14.5% annually. 10 years after it was bought, it is worth $5000. How much was the car originally worth?
A=$23,950.19
x=5 & x=-2
Iggy invested in a savings bond that was compounded continuously at 3%. After 4 years, her saving was at $57,300. About how much did Iggy originally invest?
P=$50,820.54
express log29 + log25 - log23 as a single logarithm
log215