What is the slope of this line:
y=(4/5)x-2
4/5
4c+3=7
c=1
y = −5
5x + 4y = −20
(0, −5)
Find the slope: (-19, -6), (15, 16)
11/17
What is point slope form?
y-y1=m(x-x1)
8x − 2 = −9 + 7x
x=−7
y = 4x − 9
y = x − 3
(2, −1)
Find the slope: (-3,1),(-17,2)
-1/14
Convert this into slope intercept form: 4x-3y=6
y=(4/3)x-2
4m − 4 = 8m
m=-1
x + 7y =0
2x − 8y = 22
(7, −1)
3/4
What is the equation of the line in POINT-SLOPE form that is PERPENDICULAR to y=(2/3)x-5 that passes through the point (-3,5)
y-5=(-3/2)(x+3)
−3(4x + 3) + 4(6x + 1) = 43
x=4
4x + 2y = 10
x − y = 13
(6, −7)
Parallel to y=-5x+7
-5
What is the equation of the line in SLOPE-INTERCEPT form that passes through the points (-3,2) and (3,-6)
y=(-4/3)x-2
5(2x + 6) = −4(−5 − 2x) + 3x
x=10
y = −5
5x + 4y = −20
(0, −5)
Find the slope: 2x+3y=9
-2/3