x+20=50
x=30
5c+3=18
c=3
|x+3|=2
{-5, -1}
\frac{5}{9}=\frac{g}{27}
g=15
2a-3b=4 for b
b=\frac{-4-2a}{3}
20x=100
x=5
\frac{y}{3}+5=14
y=27
|3v+5|=8
{-13/3, 1}
\frac{2}{x}=\frac{4}{28}
x=14
p=st+r for t
t=\frac{p-r}{s}
38=x-16
54
12=\frac{4-a}{2}
a=-20
no solution
\frac{y+4}{27}=\frac{14}{8}
y=17
\frac{pq+7}{2}=n for p
p=\frac{2n-7}{q}
40=\frac{a}{3
a=120
6v-4=-3v+59
v=7
Write the absolute value equation from the graph
|x-4|=3
\frac{18}{26}=\frac{3}{g+4}
g=.33
What should be on the paper for homework?
+100 points for every item correct
-Name
-Homework section
-Hour
-Numbered problems
-Only one section of homework
-Work
-Answer
\frac{4}{3}b=120
b=90
\frac{4x+10}{2}=-3x
x=-1
A company manufactures pencils that are 7.5 inches long. To pass quality inspection, the length of a pencil must be within \+-\frac{1}{8} inches of the desired length. Write an absolute value equation to find the maximum and minimum length of a pencil.
|x-7.5|=1/8
\frac{2b+14}{8}=\frac{1-2b}{12}
b=-4
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