Factor the quadratic y = x^2 - 6x + 8 and then tell me the zeros of the parabola
What is (x-2) and (x-4) and the zeros are 2 and 4.
The factors of the expression: 4x5-64x
What is: 4x(x2+4)(x+2)(x-2)
The system of equations 5x - 4y = -3 3x + 2y = 7 has the same solution as the system
(1) 5x - 4y = -3 9x + 6y = 14
(2) 5x - 4y = -3 6x + 4y = 7
(3) 5x - 4y = -3 6x + 4y = 14
(4) 5x - 4y = -3 6x + 2y = 14
What is
(3) 5x - 4y = -3 6x + 4y = 14
X= -4 is the x-coordinate of the vertex for the parabola defined by which equation?
(1) y= x2+8x+3
(2) y= x2-8x+3
(3) y= x2+4x+3
(4) y= x2-4x+3
What is (1) y= x2+8x+3
What is the value of x in the equation 4(x+2) = 1
(1) 2 (2) -1 (3) -2 (4) 0
What is (3) -2
In order to eliminate the y from the system of equations, 3x + 12y = 21 6x + 4y = 22 you could
(1) Multiply both sides of the first equation by -2
(2) Multiply both sides of the second equation by -3
(3) Multiply both sides of the first equation by -3
(4) Multiply both sides of the second equation by (1/2)
What is (3) Multiply both sides of the first equation by -3