Solve each equation by factoring.
Solve using square roots.
Solve each equation with the quadratic formula
Quadratic Basics
Word Problems
100

p2 + -2p - 15 = 0

5, -3

100

4x2 + 25 = 125

x= 5 or x = -5

100

m2 − 5m − 14 = 0

{7, −2}

100

The name given to the shape of a quadratic function

Parabola

100

The following key words tell us we are looking for which peices of the quadratic? 

a) "when- highest point"

b) "height- highest point"

c) "ground"

a) x in vertex

b) y in vertex

c) solution (x-intercept)

200

9n2 + 39n +36= 0

-4/3, -3

200

(4x + 1)2 - 16 = 0

x = 3/4 or x = -5/4

200

b2 − 4b + 4 = 0

{2}

200

The name given to the maximum/minimum point of a quadratic function

Vertex

200

A pitcher throws a ball in the air. The ball is modelled by the equation given below, where x is the time, in seconds, and y is the height, in feet. When is the ball at its peak?

y=-16x^2+96x+6

3 seconds.

300

r2 +7r+ 12 = 0

-4, -3

300

34 = (a - 2)2 - 2

a = 8 or a = -4

300

2x2 − 3x − 5 = 0

{5/2 , −1}

300

The name given to the line that splits a quadratic function into a mirror image of itself

Axis of symmetry

300

A pitcher throws a ball in the air. The ball is modelled by the equation given below, where x is the time, in seconds, and y is the height, in feet. What is the highest point that the ball reaches?

y=-16x^2+96x+6

150 ft

400

3v2 + 7v -40= 0

8/3, -5

400

0 = 3(x + 7)2 - 27

x = -10, -4

400

6n2 +4n-59 =7

x = 3, -11/3

400

How you know an equation is a quadratic

Highest exponent is 2
400

A pitcher throws a ball in the air. The ball is modelled by the equation given below, where x is the time, in seconds, and y is the height, in feet. How long is the ball in the air? (Round to the nearest tenth of a second)

y=-16x^2+96x+6

6.1 seconds

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