Solving Logs
log4(x2−2x)=log4(5x−12)
x2−2x=5x−12
Divide 3x4−5x2+3 by x+2x
31
(3x - 2) + (3x2 + 6x)
3x2 + 9x - 2
log(6x)−log(4−x)=log(3)
6x4−x=3
Divide x3+2x2−3x+4 by x−7
424
(3x2 + 2x + 1) + (2x2 - 4x - 5) + (3x - 1)
5x2 + x - 5
log3(25−x2)=2
25−x2=9
Divide 2x5+x4−6x+9 by x2−3x+1
125x−41
(2a2 + 5a + 3) -(a2 - 3a - 4)
a2 + 8a + 7
log2(x+1)−log2(2−x)=3
23=8
x3+x2+x+1 by x+9
(x+9)(x2−8x+73)−656
Subtract (2x2 + 9) from (3x - 8)
-2x2 + 3x - 17
log4(−x)+log4(6−x)=2
x=−2
7x3−17x3−1 by x+2x+2
(x+2) (7x2−14x+28)−57
Add: (x - 2) + (x + 2) + (x - 1) + (x + 1)
4x