x2-6x-7=0
x=7, x-=1
What is Standard Form of a Quadratic Function?
ax2 +bx+c
which equation has the roots for 3-i and 3+i?
1)x2 - 6x + 10 = 0
2)x2 + 6x -10 = 0
3)x2 - 10x + 6 = 0
4)x2 +10x - 6 = 0
1)x2 - 6x + 10 = 0
x=-b +/- √(b2-4ac)/2a
x2-12x-45=0
x=15, x=-3
x2-x-6=0
x=3, x=-2
3(x+2)2−27=0
x=1, x=-5
what are the steps to completing the square?
1.Rewrite the equation move the constant to the right side of the equation and leave a space for step 2.
2. Add a value to the left side to complete the square and add the same value to the right side of the equation.
3. Factor the trinomial.
4. Take the square root of both sides
5. Solve the equations.
(x-5)2+2x+1=14
x=6, x=2
6x2+11x+3=0
x=-1/3, x=-3/2
3x2+5x+7=0
x=-5/6 + i√(59/6)
The length of a rectangle is is 3 feet more than the width. If the area of the rectangle is is 18 square feet find the dimension.
x=-6, x=3
x2 - 4x - 32 = 0
x=8, x=-4
8x2+22x-21=0
x=3/4, x=-7/2
x2+8x+40=20
x=-4+2i, x=-4-2i
The width of a rectangle is 4 feet less than the length. If the area of a rectangle is 32, find each dimension
x=8, x==-4
x2-6x=-7
x=3+√2, x=3-√2
2x2+8x+3=0
x=(-4+√10)/2, - (4+√10)/2
3(x+2)2−45=0
x=√ 15 - 2, -√ 15 - 2
6*8=48