Solve
Absolute Value
Inequalities
Compound Inequalities
Absolute Value Inequalities
100

3x+9=12

X=1

100

|2x-4|=2

x=3, x=1

100

x+7>4

x>-3, open, to the right

100

x-5>0 or 3x-1<8

x>5 or x<3

100

|x-4|<7

x>-3 and x<11, open, towards each other

200

5(x+3)-4=10

x=-1/5 or -0.2

200

|-6+3|=27

x=-4, x=5

200

x-18>-15

x>13, open, to the right

200

3x+1<4 and -2x+2 < or equal to 8

x<or equal to -3 and x<1

closed and open

toward each other

200

|2k+1|>or equal to 9

k>or equal to 4 or k<or equal to -5, closed 

to the left and to the right

300

2/3x-2=5

x=21/2 , 10.5, 10 1/2

300

|5-2x|-11=0

x=-3, x=8

300

3-(4m+1)>5m-25

equal to

3> or equal to m, closed and to the left

300

when do I use a bracket and when do I use parenthesis?

Bracket= closed circle and parenthesis when open circle or by an infinity

300

When I multiply or divide by a negative what happens to the sign

it flips

400

10-(8p+3)=9(2p-5)

p=2

400

-2|x-4|+3=1

x=5, x=3

400

3(x-4)< or equal to x-6

x<or equal to 3, closed, to the left

400

write x<-5 or x>15 in interval notation

(-infinity, -5) U (15, infinity)

400

When Im writing the second equation what happen to the signs and what happens to the number on the other side of the equal sign?

sign flips and you change the number to positive or negative depending what it is first.

500

3x-5/4=x+1/2

x=7

500

-7|9-2x|+9=-12

x=3, x=6

500

4+5(2w-10)/-2=x+7

w>5, open, to the right

500

write n<or equal to 13 and n>or equal to -1 in interval notation

[-1,13]
500

9-2|4x+1|>3

x>4 and x<-1, open, towards each other

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