Forenkle algebraiske uttrykk
3x+4x=
7x
x + 3 = 7
x= 4
2(x+3)
2x+6
2(x+3)=10
x=2
1/2 * 6
3
5a+7 - 2a=
3a + 7
2x = 10
x = 5
(3y + 2) - (y+5)
2y - 3
3(x-2) =12
x=2
12/4 + 3
6
6y - 3 + 2y +5
8y +2
2x - 5 = 11
x = 3
3(x+4) + 2x -2
5x +10
x=6
2/5 * 10
20/5 = 4
10x- 5y +3y + 3
10x- 2y + 3
3x + 4 = 19
x= 5
6x+ 7(x-2) -(2x + 5)
11x - 9
2(x+4)/2 = 10
x=6
2/3 * (9-3)
18/3 - 6/3 =
6- 2= 4
7m + 4n - 2m + 3n -5
9m + 7n -5
5x - 7 = x + 9
x= 4
3(x+4) - 2+4(x-5)
7x - 10
(3(x+2)+6)/3 = 5
x= 1
3(4+2) / 6
18/6 =
3