Find an equation for the inverse of the relation y =3x - 5
y = 1/3 x + 5/3
bc. x = 3y -5
x + 5 = 3y
1/3 x + 5/3 = y
300
State the Domain & Range.
y = -2(x-3)^(1/2) + 2
Domain: x is greater or equal to 3.
Range: y is less than or equal to 2.
300
Solve (2x + 7)^(1/3) = 3.
x = 10
bc. ((2x + 7)^(1/3))^3=3^3
2x + 7 = 27
2x = 20
x =10
400
Factor completely:
y^4-x^4
(y-x)(y+x)(y^2+x^2)
400
f(x)=x^2-x and g(x)= x-2
Find f(g(x))
What is x^2-5x+6
400
Find the inverse of f(x) = -10x^6 , x</ 0
f^-1 (x) = - ( x/-10)^(1/6)
400
What transformation was used to produce the graph of g(x) from the graph of f(x)
f(x) = 2x^3-1 and g(x)=2x^3 +5
vertical shift up 6
400
Solve.
x+1 = (7x + 15)^(1/2)
x = 7
bc. (x+1)^2 =( (7x + 15)^(1/2))^2
x^2 +2x +1 = 7x +15
x^2 -5x-14=0
(x-7)(x+2) =0
x=7 or x =-2
500
SOlve: 3x^2-10x=-5
What is x= (5+/- sqr 10)/3
500
f(x)=4x^2-4xy+x-y and g(x)= 2x^2-xy-y^2
Find (f/g)(x)
What is (4x+1)/(2x+y)
500
F(x)=2x-3
what is f^-1(-3)?
What is 0
500
The graph of y=x^2 is shifted two units left, vertically compressed by 1/2, reflected over the y-axis and shifted up 3 units. Write the equation for the transformed function