Algebra II Exam #1

Solving Linear Equations

100

x + 3 - 3 = -6

x = -6

200

-3(4r-8) = -36

r - = 5

300

5(4x-9)-2x=6x +15

x = 5

400

12(2k+11)=12(2k+12)

no solution

500

10p+9-11-p=-2(2p+4)-3(2p-2)

0

Solving Linear Inequalities

100

-1 < 2n +4 -5

x > 0

200

7 < −(−k − 3) + 2

x > 2

300

−5(1 − 4a) > −5

a > 0

400

26 + m ≥ 5(−6 + 3m)

m ≤ 4

500

−6(1 + 2x) ≥ 6(2x − 1) + 2x

x ≤ 0

Addition Property

100

if x = 4 what is the value of 3x + 5x - 10

22

200

If x + 2 = 4 what is the value of 3x + 5 

11

300

If 6x - 12 = 20 what is the value of 6x + 6

16 / 3

400

If 8y - 7 =3 what is the value of 8y + 2

5 / 4

500

If 3m + 5 = 23 what is the value of 2m - 3

6

Write and Equation Passing Though Pair of Points

100

(5, 3) and (2, 3)

y = 3

200

(2,7) and (0, 1)

y = 3x +1

300

(3, 4) and (5,8)

y=2x-2

400

(4,5) and (8, 3)?

y = -1/2x + 7

500

(1,2) and (5, 10 )?

y = 2x

Parallel and Perpendicular

300

y = 3x +6 (4,7) - that is parellel

y = 3x - 5

500

(-4, 2) perpendicular to y = 23x - 3

y =. -1/23x + 42/23