Writing Equations
Solving Equations
Creating Graphs
Solving Quadratics
Miscellaneous
100

Write the equation of the function g(x) whose graph represents the indicated transformation of the function f(x)=4x+3; g(x) has undergone a vertical shrink by a factor of 1/3.

g(x)=4/3x+12

100

Solve for k.

|k+8|>2

k>-6 or k<-10

100

Graph f(x)=2x-2

Describe the transformation from f(x)=x

Transformation: Vertical stretch by a factor of 2, translated down 2.

100

x2 - 2x=0

x=0,2

100

Simplify:

i23

-i

200

Write the equation of the function g(x) whose graph represents the indicated transformation of the function f(x)=|3x|+2; g(x) has undergone a horizontal shrink by a factor of 1/3.

g(x)=|9x|+2

200

Solve for x.

|x+4|+7=3

No solution.

200

Graph f(x)=|x-2|+3

Describe the transformation from the graph f(x)=|x|

Transformation: Translated to the right 2, up 3.

200
Solve for x.

x+4=0

x= 2i, -2i

200

Identify the focus, directrix, and axis of symmetry:

y=1/12x2

Focus: (0,3)

Directrix: y=-3

AoS: x=0

300

Write the equation of f(x) given that the vertex of f(x) is (2,-3) and f(x) passes through the point (6,4)

f(x)=7/16(x-2)2 -3

300

|b+3|=|2b-2|

b=5, b=-1/3

300

Graph f(x)=(x+2)2 +4

Label the vertex and axis of symmetry. 

Vertex=(-2,4)

AoS: x=-2

300

Solve for h by completing the square:

h2-10h-4=0

h=5+sqrt(29), 5-sqrt(29)

300

Find a possible pair of integer values for a and c such that the following quadratic has two imaginary solutions.

ax2-5x+c=0

Any a,c such that:

25-4ac<0

400

Write the equation of f(x) given that f(x) has x-intercepts of 10 and 6, and f(x) passes through the point (11,8).

f(x)=8/5(x-10)(x-6)

400

Solve for x and y.

2x+y=5

x-y=1

(x,y)=(2,1)

400

Graph f(x)=-x2+2

Label the vertex and axis of symmetry.

Vertex: (0,2)

AoS: x=0

400

Solve for x.

(x-3)2=25

x=8, -2

400

Simplify:

sqrt(-49/9)

7/3i

500

Write the equation of f(x) given that f(x) has a focus at (0,2) and a vertex at (0,0)

f(x)=1/8x2

500

Solve for x, y, and z.

y=-3

2x+y=5

x-2y+z=6

(x,y,z)=(4,-3,-4)

500

Graph f(x)=-x2 -2x +1

Label the vertex and axis of symmetry.

Vertex: (0,1)

AoS: x=1

500

Solve for x using the quadratic formula.

2x2-2x-4=0

x=-1,2

500

Find the value of c that makes the expression a perfect square trinomial:

y2+26y+c

c=169

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