Transfo-mations
SolvN fo X
FactAh
Functions wit x
Use dat CalculatAh
100
What is the equation of a parabola shifted up 4 units and reflected across the x a-axis?
-(x^2)+ 4
100
3x + 1 < 7
x < 2
100
If a polynomial has -9 as a zero, what is its factor?
(x + 9 )
100
Find fog(x) where f(x)= x^2 and g(x)= x+1.
(x+1)^2 or x^2 + 2x + 1
100
Solve the system by graphing. y = x - 2 and y= -x+10 The solution is ( , )
What is (6, 4)
200
1/2 (x^2 - 4) : How does multiplying the function by 1/2 change the parabola?
1/2 stretches the parabola (makes it fat)
200
-4y > 8x - 2
y < -2x + 1/2 (the sign changes when you multiply or divide by a negative)
200
Factor : x^2 - 36
(x + 6 ) (x - 6)
200
What is the degree of x, where y = 5x^3 + 2x^2 -1
third degree or cubic
200
The solution of the following system x + y = -1 and x - y =3 is...
No solution (The lines are parallel)
300
What is the vertex of the parabola? y = -3(x + 4) - 1
Vertex Form is y = a(x - h)^2 + k vertex is ( h, k) Answer: ( -4 , -1)
300
5x^2 - 45 =0
x = -3, +3 (when you square root both sides make sure you put + and- on the right side)
300
Factor: x^2 - 11x + 18
(x - 9) (x - 2)
300
Define binomial
A polynomial with two terms ex: x^2 + 3x
300
What is/are the zero(s) for the following polynomial: f(x) = x^3 +6x^2 +9x
{-3, 0 }
400
Write the equation of an absolute value function shifted down 2 units, compressed by 5, and shifted left 3 units.
y = 5| x + 3 | -2
400
|6x - 15| = 3
x = 3 and 2 (when you have an abs. val. set the equation equal to a positive solution and another to a negative solution)
400
Formula for sum of cubes: x^3 + y^3 =
(x + y) ( x^2 - xy + y^2 )
400
Find gof(x) , where f(x) = x^3 and g(x) = x-5
x^3 - 5
400
Is the function increasing or decreasing in the interval 0
Decreasing
500
Write an abolsute value function with a vertex at (-5, 2) and reflected across the x-axis.
y = - | x + 5| +2
500
2 / (x+2) + 5/ (x-2) = 6/ x^2 - 4
x = 0 ( the lcd is (x+2)(x-2) )
500
Factor then Simplify: x^2+ 13x + 40/ x^2 - 2x - 35
(x + 8)/ (x - 7 )
500
y varies jointly with x and q and inversely with 3z
y = kxq/ 3z
500
As x approaches negative infinity y approaches... ,where f(x) =
positive infinity
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