TERMS
CONVERSION
IDENTIFICATION
COMPUTATION
Final jeopardy
100

Is the study that deals with the nutrients and their utilisation by the animal

NUTRITION

100

7%= PPM

70,000

100

It is used when the concentration of the nutrient is very small


Parts Per Million (ppm)

100

Find the % of DM if the given moisture content is 11.5%.

89.5%

200

a chemical element or compound that is essential for the normal body metabolism

NUTRIENT

200

26400 ppm = %

2.64 %

200

This expresssion is commonly used in countries where imperial units are preferred.

MILLIGRAM PER POUND (mg/lb)

200

A fresh forage contains:

  • Moisture = 29%
  • Crude Protein = 9%

Convert the crude protein to a oven Dry Matter basis.

12.676%

300

refers to feed in its NATURAL STATE, including all moisture content.

AS-FED BASIS (WET OR FRESH BASIS)

300

Kg = lbs

9.8 kgs = lbs

9.8 x 2.2

=21.56 lbs

300

It is the most basic and widely used form of nutrient expression 

PERCENTAGE (%)

300

 A feed sample contains:

  • Moisture = 31%
  • Crude Protein = 26%
  • Ether Extract = 6.6%

Convert both nutrients to an Air-Dry Basis.

CP = 33.91%

EE = 8.61%

400

Most commercial feeds and forages are considered to be

AIR-DRY BASIS

400

mg/g ---> %

630 mg/g

1 mg/g = 0.1%

63%

400

the overall composition or mix of feeds an animal eats.

DIET-

400

A hay sample contains:

  • Dry Matter = 72%
  • Crude Fiber (DM Basis) = 29%
  • Ether Extract (DM Basis) = 3%

Express both nutrients on an As-fed Basis.

CF = 20.88%

EE = 2.16%

500

represents everything contained in a feed sample except water; this includes protein, fiber, fat, minerals, etc.

DRY MATTER

500

microgram = ounce (oz)

90,000,100

mcg->mg->g->kg->

90,000,100 ÷ 1000 ÷ 1000 ÷ 1000 x  35.27

3.14 oz

500

the daily food allowance

RATION

500

A commercial poultry feed has the following proximate composition:

  • Moisture = 10%
  • Crude Protein = 17%
  • Ether Extract = 6%
  • Crude Fiber = 49%
  • Ash = 9%
  • Nitrogen-Free Extract (NFE) = 28%

Question:

Compute the total carbohydrate content of the feed.


Carbohydrates = NFE + CF

= 28 + 49 

=77

500

Based on the orientation on waste segregation, which waste is the last option?

Residual Wastes

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