β«(5π₯4 +8π₯3 β9π₯2 β1)ππ₯
π₯5 + 2π₯4 β3π₯3 β π₯ + πΆ
β«Cos(5x+3)(5) dx
Sin(5x+3)+C
β«-68 10 dx
140
dy/dx = x-4; y(2)=0
y = x2/2 - 4x + 6
β«-147 (7ex) dx
7e7-7e-14
β«(π₯1/4 + 1/βπ₯ +1/π₯ β 1/π₯2)ππ₯
(4/5)x5/4 - 2βx + ln lxl + 1/π₯ + c
β«(4x6+7)12(24x5) dx
(4x6+7)13/13 +C
β«02 (4x3-3x2+2x) dx
12
ππ¦/ππ₯ = 3/π₯2; π¦(1)=2
π¦=β3/π₯ +5
β« 2/(1βπ₯2)1/2 ππ₯
2sinβ1 π₯+πΆ
β«(ππ₯ +secπ₯tanπ₯βtanπ₯) ππ₯
ππ₯ +secπ₯+ln|cosπ₯|+πΆ
β«(7x+4)9 dx
(1/7)(7x+4)10/10 + c
β«-2-1(6/x3) dx
-9/4
y'=x2-1; y(3)=7
y=(x3/3)-x+1
β«8 sin(5x) dx
(-8/5) cos(5x) + C
β«(3π₯ + 4/(1+π₯2))ππ₯
(1/(ln3))3π₯ +4tanβ1 π₯+πΆ
β«1/(1+(4x)2) dx
1/4 tan-1(4x)+C
β«02 (x/(1+2x2)2 dx
2/9
π¦β² =sinπ₯; π¦(0)=5
π¦=βcosπ₯+6
ππ§/ππ‘ =cosπ‘β2sinπ‘; π§(0)=5
π§(π‘)=sinπ‘+2cosπ‘+3
β« 5π₯3/(1+π₯4) ππ₯
(5/4)ln|1+π₯4|+πΆ
β«sec7x tan x dx
(sec x)7/7 + C
β«0π (sec2(x/3)) dx
3β3
dy/dx=2/(x+1); y(0)=2
2ln|π₯+1|+2
d2y/ dx2= 4-3x ;y'(0)=5 & y(0)=7
y'=4x-((3x2)/2)+5
y''=2x2-(1/2)x3+5x+7