400
By pushing a rectangle into a circle with a radius of one meter, you can cover at most this much surface area.
What is 2 square meters?
Solution: This is easier to show via graphing, but that doesn't work in this format, so this'll get complicated. Imagining our circle as one centered on the point of origin in a standard x,y coordinate grid, we can define the rectangle we're trying to construct as an extrapolation of a single point, (a vertex of the rectangel), in coordinate 1 (on the edge of the circle), as the perfect symmetry of our circle would naturally leave the other 3 corners obvious. This gives us two nonnegative x,y values to shoot for. The area we're looking to maximize can be defined as A=2x*2y or 4xy Optimizing for x gives us
x= sqrt(1-y^2), so we can give area as 4y*sqrt(1-y^2). Derivative=-4y^2/sqrt(1-y^2), thus 4-8y^2/sqrt(1-y^2), and at this point it's fairly obvious our critical points are 1 and sqrt(1/2) (we can dispose of the extraneous negative answers, as we're in the first quadrant). y being at 1 would naturally give us a perfect line of a rectangle, ergo we plug in sqrt(1/2) into a(y), giving us our final value of 2.