what color is aiden
white
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what is blue eyes and blond hair
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what is 271k (lose a billion points if you say 6m)
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sakura
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mcdondal
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milk way
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RoR
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taco bell
isreal?
good
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who is yakub
has isreal ever done anything bad
no
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HxH
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arby
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mr beast
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hyperborea
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Aizen
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red lobster
solve the following:
A particle of mass mmm and electric charge qqq is constrained to move on a 1-dimensional ring of radius RRR (coordinate θ∈[0,2π)\theta\in[0,2\pi)θ∈[0,2π)). A magnetic flux Φ\PhiΦ threads the ring (vector potential can be chosen A=(Φ/2πR) θ^\mathbf{A} = (\Phi/2\pi R)\,\hat{\theta}A=(Φ/2πR)θ^ on the ring).
Write and solve the time-independent Schrödinger equation to find the energy eigenvalues En(Φ)E_n(\Phi)En(Φ) and normalized eigenfunctions ψn(θ;Φ)\psi_n(\theta;\Phi)ψn(θ;Φ).
Compute the persistent current In(Φ)I_n(\Phi)In(Φ) carried by the eigenstate nnn defined as
In(Φ)=−∂En(Φ)∂Φ.I_n(\Phi) = -\frac{\partial E_n(\Phi)}{\partial \Phi}.In(Φ)=−∂Φ∂En(Φ).
State which nnn is the ground-state index at zero temperature (qualitatively) and give the ground-state current.
On the ring the minimal-coupling Hamiltonian (in the θ\thetaθ coordinate) is
H^=12m(p^θ−qAθR)2,p^θ=−iℏ∂∂θ,\hat H = \frac{1}{2m}\left(\frac{\hat p_\theta - qA_\theta}{R}\right)^2, \qquad \hat p_\theta = -i\hbar\frac{\partial}{\partial\theta},H^=2m1(Rp^θ−qAθ)2,p^θ=−iℏ∂θ∂,
and with Aθ=Φ2πRA_\theta=\dfrac{\Phi}{2\pi R}Aθ=2πRΦ (a gauge choice appropriate for the ring) this becomes
H^=12mR2(−iℏ∂∂θ−qΦ2π)2.\hat H = \frac{1}{2mR^2}\left(-i\hbar\frac{\partial}{\partial\theta} - \frac{q\Phi}{2\pi}\right)^2.H^=2mR21(−iℏ∂θ∂−2πqΦ)2.
Look for eigenfunctions of the form ψ(θ)=12πeinθ\psi(\theta)=\dfrac{1}{\sqrt{2\pi}}e^{i n\theta}ψ(θ)=2π1einθ with integer nnn (single-valuedness requires n∈Zn\in\mathbb{Z}n∈Z). Acting with H^\hat HH^ gives
H^ψn=12mR2(ℏn−qΦ2π)2ψn.\hat H \psi_n = \frac{1}{2mR^2}\left(\hbar n - \frac{q\Phi}{2\pi}\right)^2 \psi_n.H^ψn=2mR21(ℏn−2πqΦ)2ψn.
Define the dimensionless flux φ≡ΦΦ0 \displaystyle \varphi\equiv\frac{\Phi}{\Phi_0}φ≡Φ0Φ where Φ0\Phi_0Φ0 is the flux quantum for charge qqq:
Φ0≡hq(so φ=Φ/Φ0).\Phi_0 \equiv \frac{h}{q}\quad(\text{so } \varphi=\Phi/\Phi_0).Φ0≡qh(so φ=Φ/Φ0).
Note h=2πℏh=2\pi\hbarh=2πℏ. Then qΦ2π=ℏφ\dfrac{q\Phi}{2\pi} = \hbar\varphi2πqΦ=ℏφ. Thus the eigenenergies simplify to
En(Φ)=ℏ22mR2(n−φ)2,n∈Z \boxed{\,E_n(\Phi)=\frac{\hbar^2}{2mR^2}\bigl(n-\varphi\bigr)^2,\qquad n\in\mathbb{Z}\,}En(Φ)=2mR2ℏ2(n−φ)2,n∈Z
and the normalized eigenfunctions are
ψn(θ;Φ)=12πeinθ \boxed{\,\psi_n(\theta;\Phi)=\frac{1}{\sqrt{2\pi}}e^{i n\theta}\,}ψn(θ;Φ)=2π1einθ
(you can view the flux as shifting the effective angular momentum by ℏφ\hbar\varphiℏφ).
who invented the agarthan theory
saint-yves d'alveydre
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all of it
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who sells the aura
john pork