Boyle
If you squeeze a balloon to reduce its volume, what happens to the pressure inside the balloon, assuming constant temperature?
Pressure increases
What temperature scale do we have to use for Charles' Law?
Kelvin
Kelvin is an absolute scale, so it avoids negative temperatures that would make the math invalid.
The variables in this law are DIRECTLY proportional
Charles' Law
A gas has an initial volume of 12.0 L at 100 kPa. What will its volume be if the pressure increases to 200 kPa?
6.0 L
A gas has a volume of 8.0 L at a pressure of 150 kPa. If the pressure increases to 300 kPa, what is the new volume?
4.0 L
A gas has a volume of 10.0 L at a temperature of 273 K. If the temperature increases to 546 K, what is the new volume?
20.0 L
The variables in this law are DIRECTLY proportional
Boyle's
The equation to convert ºC to K
K = ºC + 273.15
A gas at 1.2 atm occupies a volume of 3.0 L. What will the volume be if the pressure decreases to 0.8 atm, assuming constant temperature?
4.5 L
A gas occupies 5.0 L at 300 K. If the volume decreases to 2.5 L, what is the final temperature?
150 K
A basketball left in the cold shrinks as the temperature drops. Which law explains this phenomenon?
Charles' Law
A gas occupies a volume of 15.0 L at 350 K. If the temperature decreases to 175 K, what will the new volume be?
7.5 L
What happens to the volume of a gas if the pressure doubles, assuming temperature remains constant?
the volume is halved
If the temperature of a gas doubles in Kelvin, what happens to its volume, assuming constant pressure?
The volume also doubles.
The equation for Boyle's Law
P1V1=P2V2
A gas has a volume of 5.0 L at 27°C. If the volume increases to 10.0 L, what is the new temperature in Kelvin? Hint: Convert 27ºC to Kelvin using K = C + 273.15
600K
Why does Boyle's Law only apply when temperature is constant?
Change in temperature would also change the energy of gas particles, affecting volume or pressure independently.
If you inflate a balloon at sea level and take it to a high-altitude mountain where it is colder, what will happen to its size, and why?
The balloon will shrink because the temperature is lower, reducing the volume.
The equation for Charles' Law
V1/T1 = V2/T2
A gas occupies 10.0 L at a temperature of 25°C. If the volume expands to 20.0 L, what is the new temperature in Celcius? HINT: two conversions using the equation K = C + 273.15
323 ºC