The slope of the tangent line equaling this number would mean a max or min at that point ?
0
Find the derivative of y = 3x4*sin x
4x3 sin x + 3x4 cos x
Find y' if y = (3x2 - 5)6
36x(3x2 - 5)5
Find the derivative implicitly x4 + y2 = 2x
y' = (1/y)-(2x3/y)
Derivative of secx
secxtanx
This is used to determine the concavity of a function
f(x) = (3x - 2x2)/(5 + 4x)
(-8x2-14x+15)/(5+4x)2
Find the derivative of f(x) = tan(7x5+3x)
(35x4+3)sec2(7x5+3x)
x2y+y = 6
y' = (6-2xy)/(x2+1)
Daily Double
-3x2csc(x3)cot(x3)
Besides the derivative equaling 0, there must also be a _________________ for the function to have a maximum.
sign change
Find the derivative of y = ln(4x2)/e6x
(2/e6x)-(((6xln(4x2))/(e6x))
Find y' if y = 1/(9x2 + 4)1/2
-(18x)/(9x2 + 4)3/2
(4y - 2)3 = 6x - 12
y' = 1/(2(4y - 2)2)
Derivative of sin-1x
1/(1-x2)1/2
How is acceleration related to position?
second derivative
Daily Double
Calculate the derivative of (csc(x2)tan(x2))/-sec(x2)
0
f(x) = log8(cos(x2)) Find f'(x)
(-2/ln8)*x*tanx2
tan(xy)+sin(y2)= 4
y' = (-ysec2(xy))/(xsec2 (xy)+ 2cos(y2))
Derivative of tan-1x
1/(1+ x2)
The third derivative of position is
jerk
(lnx*sinx3)/log3(x2)
(((1/x*cos(x3)-3x2lnx*sin(x3))/log5x2)-
(((2/ln5)*lnxcos(x3))/(log5x2)2
Differentiate: 3sec(5x^3)
15ln3x*3^sec(5x^3)*sec(5x^3)tan(5x^3)
xsin(x3)+3ycos(y2)=y3
(sin(x3)+3x3*cos(x3))/(3y2+6y2*sin(y2)-3cos(y2))
Derivative of sec-1(5x2)
10x/ (l5x2l ((25x4-1)1/2)