Integral Review
F.T.C.
Oh That Crazy S Word
Areas
Va-Va-Volumes
100

\int4x^2+x+3\ dx

4/3x^3+x^2/2+3x+C

100

Use the Fundamental Theorem of Calculus to evaluate the following integral:

∫_0^8(3+x)dx

56

100

∫x^2/(sqrt(x^3+3))\ dx

2/3 sqrt(x^3+3)+C

100

Use a right endpoint rectangular model to estimate the area under the curves below using 6 rectangles of equal width:

f(x)=x^2, x = 0 and x = 3

11.375

100

Find the volume: The solid lies between planes perpendicular to the x-axis at x= -4 and x= 4. The cross sections perpendicular to the x-axis are circular disks whose diameters run from the parabola y = x² to the parabola y = 32 - x²

16384/15 * π

200

\int2x-9sin(x) dx=

x^2+9cos(x)+C

What is x2 + 9cosx+C

200

Use the Fundamental Theorem of Calculus to evaluate the following integral:

∫_-1^1(4x^3-2x)\ dx

0

200

∫x(1-3x^2)^4\ dx

-1/30(1-3x^2)^5 +C

200

Find the total area of the region between:

y= 2x + 7, y=0, x = 1 , x = 5.

52

200

Find the volume of the solid generated by revolving the region bounded by the given lines and curves about the x-axis.

y = \sqrtx, y = 0, x = 0, x = 9

81/2 * π

300

\intt+e^t \ dt

t^2/2+e^t+C

300

Use the Fundamental Theorem of Calculus to evaluate the following:

d/dx[∫_0^(x^5)sin(t)\ dt]

5x^4 * sin(x^5)

300

∫(sinx)^3cosx\ dx

1/4(sinx)^4+C

300

Find the area of the total region enclosed by the curves:

f(x) = x³+x²-6x,g(x) = 6x

937/12

300

Find the volume of the solid generated by revolving the region bounded by the curves about the x-axis.

y = -6x + 12, y = 6x, x = 0

72π

400

\int10/x\ dx

10ln|x| + C

400

Use the Fundamental Theorem of Calculus to evaluate:

∫_1^6(3/x)\ dx

3ln(6)

400

∫xe^(-3x^2)\ dx

-1/6e^(-3x^2)+C

400

Find the area enclosed by the curves:

y = 2x - x², y = 2x - 4

32/3

400

Find the volume of the solid generated by revolving the region about the y-axis. The region in the first quadrant bounded on the left by y = x³, on the right by the line x = 4, and below by the x-axis.

2048/5 * π

500

\int6(5^x)\ dx

6/ln(5)5^x + C

500

Use the Fundamental Theorem of Calculus to evaluate:

d/dx[∫_-2^2t(t^2-6)dt]

0

500

∫(x^2 + 16)^(1/2]/(x^4)\ dx

−[(x^2+16)^(3/2)]/(48x^3)+C

500

Find the area enclosed by the curves:

y = x and y = x^2

1/6

500

The region shown is to be revolved about the x-axis to generate a solid. Which of the methods (disk/washer, shell) could you use to find the volume of the solid? How many integrals would be required in each case?

Washer+Disk (2 integrals), Shell (1 integral)

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