chain rule
implicit differentiation
derivative of inverse trigonometry
second derivatives
combination
100

sin(3x)

3cos(3x)

100

x^2=3y

dy/dx=(2x)/3

100

tan^-1x

dy/dx=1/(1+x^2)

100

y=x^4+3x

(d^2y)/dx^2=12x^2

100

3sin(y+6x)=x^5, fi nd dy/dx

dy/dx=(5x^4-6)/(3cos(y+6x)

200

3e^(3x)

9e^(3x)

200

x^3-e^x=e^y-2y

dy/dx=(3x-e^x)/(e^y-2)

200

sin^-1x

dy/dx=1/(sqrt(1-x^2))

200

y=x^5+sinx

(d^2y)/dx^2=16x^2-sinx

200

y=tan^-1(x^2+2), fi nd dy/dx

dy/dx=(2x)/(1+(x^2+2)^2

300

-6cos(2x^2)

24xsin(2x^2)

300

x+siny=-cosx

dy/dx=(sinx-1)/cosy

300

cos^-1x

dy/dx=-1/sqrt(1-x^2)

300

y=sqrt(x)+x^-2

(d^2y)/dx^2=-1/4x^(-3/2)+6x^-4

300

y=root(3)x +5x^4 , fi nd (d^2y)/dx^2

(d^2y)/dx^2=-2/9x^(-5/3)+60x^2

400

(6x+x^2)^2

4x^3+36x^2+72x

400

6x^3-x^2+3x=y^2+3y

(18x^2-2x+3)/(2y+3)

400

sec^-1x

dy/dx=1/(|x|sqrt(x^2-1))

400

y=sinx+ln(5x)

(d^2y)/dx^2=-sinx(-5/x^2)

400

if y=sin^2x+e^x , then  (d^2y)/dx^2 =

(d^2y)/dx^2= -2sin^2x+2cos^2x+e^x

500

(log_5x+2x^2)^4

4(log_5x+2x^2)(lnx/ln5 +4x)

500

6xy^2+e^(y+7)=cos^2x

dy/dx=(-2cosxsinx-6y^2)/(12xy+e^(y+7))

500

csc^-1x

dy/dx=-1/(|x|sqrt(x^2-1))

500

y=e^x*x+2x^2

(d^2y)/dx^2=xe^x+e^x+4x

500

4y^2=2(sin(y)-lnx)^(1/3)+sqrty

dy/dx=(2/3(siny-lnx)^(-2/3))/(8y-(1/2)y^(-1/2)

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