Recall the Derivative!
All Types of Limits!
Derivatives Rule!
Fill in the Blank
Random Topics
100

(5 seconds) 

d/dx(x^n)

nx^(n-1)

100

(30 seconds) 

lim_(t->-3)(6+4t)/(t^2+1)

-3/5

100

(1 minute 30 seconds)

d/dx((sqrt(x)+x^(9/4)-1)/x^2)

-3/2x^(-5/2)+1/4x^(-3/4)+2x^(-3)

100

(15 seconds) If r is a positive rational number and c is any real number then,

lim_(x->oo)c/x^r=?

0

100

(15 seconds) 

lim_(x->0)sin(x)/x

1

200

(5 seconds)

d/dx(c)


0

200

(45 seconds) 

lim_(x->oo)(2x^4-x^2+8x)/(-5x^4+7)

-2/5

200

(1 minute)

d/dx(e^(1-cos(x)))

sin(x)e^(1-cos(x))

200

(15 seconds) Fill in the following statement with either continuous or differentiable:

If f(x) is (1) x=a then f(x) is (2) at x=a 

1) differentiable 

2) continuous

200

(1 minute) A rock's height in meters while falling off a cliff is given by the function h(t). What is the rock's acceleration in meters per second at t=5 seconds? (Hint: The acceleration is the second derivative of the position)

-9.8 m/s^2

300

(10 seconds)

d/dx(secx)

secxtanx

300

(30 seconds)

lim_(x->oo)arctan(x)

pi/2

300

(1 minute 30 seconds) Do not simplify!

d/dx(x/(1+sqrtx))

((1+sqrtx)*1-x*(1/(2sqrtx)))/(1+sqrtx)^2

300

(20 seconds) A function f(x) is said to be continuous at x=a if:

?=f(a)

lim_(x->a)f(x)

300

(1 minute 30 seconds) Given that the below function has a y-intercept at (0,25) find the equation of the tangent line to that function at that point.

y=16e^x-sinx+4x+9

y=19x+25

400

(15 seconds) 

d/dx(log_a(x))

1/(xlna)

400

(1 minute)

lim_(h->0)(sqrt(9+h)-3)/h

1/6

400

(1 minute) Use implicit differentiation to solve for dy/dx:

e^x-sin(y)=x

dy/dx=(1-e^x)/-cos(y)=(e^x-1)sec(y)

400

(30 seconds) Suppose that f(x) is continuous on [a,b]  M be any number between f(a) and f(b). Then there exists a number c such that,

1. a<(1)<b

2. (2)=M

1) c 

2) f(c)

400

(2 minutes) Find C such that the piecewise function below is continuous.

f(x)=x^2-C if x<=5, 

f(x)=(4x-20)/(x^2-6x+5) if x>5 

C=24

500

(15 seconds)

d/dx(cos^-1(x))

-1/sqrt(1-x^2)

500

(1 minute 30 seconds)

lim_(x->0)x^2cos(1/x)

By using Squeeze theorem, we find the limit is equal to 

0

500

(2 minutes)

d/dx(ln((xsinx+1)^2))

(2(sinx+xcosx))/(xsinx+1)

500

(30 seconds) Fill in the blank for the limit definition of the derivative:

lim_(h->0)?=f'(x)

(f(x+h)-f(x))/h

500

(2 minutes) Find the derivative dy/dx for the following function (Hint: Use logarithmic differentiation).

y=x^x

dy/dx=y(1+lnx)=x^x(1+lnx)

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