Polynomials
Solve
Theroems
Simplify
Division
100

State the degree and Leading coefficient:

12x2-5x4+6x8-3x-3

8 and 6

100

Solve:

x3+2x2-35x=0

-7,0,5

100

Find f(-2) by synthetic substitution:

f(x)=x2-5x+4

18

100

Simplify:

3t(tn-5)

3t2n-15t

100

Divide:

(12x4y5+8x3y7-16x2y6) / 4xy5


3x3+2x2y2-4xy

200

Find P(-2)

P(x)=3x- x

14

200

Solve:

8x4-10x2+3=0

+- Sqrt(3)/2, +- Sqrt(2)/2

200

Find f(4) by synthetic substitution:

f(x)=2x4-3x3+1

321

200

(x4)3

x12

200

Divide:

6y3+13y2- 10y-24 /  (y+2)

6y2+y-12

300

Find P(x+h)

P(x)=3x- x

3x2+6xh+3h2-x-h

300

Solve:

4x3+4x2-x-1=0

-1, -1/2, 1/2

300

State the number of possible zeros:

f(x)= -2x3+11x2-3x+2

3

300

3b(2b-1) + 2b(b+3)

8b2+3b

300

Divide:

4a6-5a4+3a2-a / (2a+1)

2a5-a4-2a3+a2+a-1 R:1

400

Factor:

a4-16

(a-2)(a+2)(a2+4)

400

Solve:

x3+4x2-11x-30=0

3, -2, 5

400

State the number of possible turning points:

f(x)= x6-5x3+x2+x-6

5

400

(-4a3b5)(5ab3)

-20a4b8

400

Divide:

6x3-31x2-34x+22 / (2x-1)

3x2-14x-24 R: -2

500

Factor:

6ay + 4by - 2cy + 3az + 2bz - cz

(2y+z)(3a+2b-c)

500

Solve:

x3+2x2+4x+8=0

-2, 2i, -2i

500

State all possible rational zeros:

f(x)= x3+4x2-11x-30

+- 1, 2, 3, 5, 6, 10, 15, 30

500

(2x2+3x-8)+(3x2-5x-7)

5x2-2x-15

500

Divide:

3x3+11x2-114x-80 / (3x+2)

x2+3x-40

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