State the degree and Leading coefficient:
12x2-5x4+6x8-3x-3
8 and 6
Solve:
x3+2x2-35x=0
-7,0,5
Find f(-2) by synthetic substitution:
f(x)=x2-5x+4
18
Simplify:
3t(tn-5)
3t2n-15t
Divide:
(12x4y5+8x3y7-16x2y6) / 4xy5
3x3+2x2y2-4xy
Find P(-2)
P(x)=3x2 - x
14
Solve:
8x4-10x2+3=0
+- Sqrt(3)/2, +- Sqrt(2)/2
Find f(4) by synthetic substitution:
f(x)=2x4-3x3+1
321
(x4)3
x12
Divide:
6y3+13y2- 10y-24 / (y+2)
6y2+y-12
Find P(x+h)
P(x)=3x2 - x
3x2+6xh+3h2-x-h
Solve:
4x3+4x2-x-1=0
-1, -1/2, 1/2
State the number of possible zeros:
f(x)= -2x3+11x2-3x+2
3
3b(2b-1) + 2b(b+3)
8b2+3b
Divide:
4a6-5a4+3a2-a / (2a+1)
2a5-a4-2a3+a2+a-1 R:1
Factor:
a4-16
(a-2)(a+2)(a2+4)
Solve:
x3+4x2-11x-30=0
3, -2, 5
State the number of possible turning points:
f(x)= x6-5x3+x2+x-6
5
(-4a3b5)(5ab3)
-20a4b8
Divide:
6x3-31x2-34x+22 / (2x-1)
3x2-14x-24 R: -2
Factor:
6ay + 4by - 2cy + 3az + 2bz - cz
(2y+z)(3a+2b-c)
Solve:
x3+2x2+4x+8=0
-2, 2i, -2i
State all possible rational zeros:
f(x)= x3+4x2-11x-30
+- 1, 2, 3, 5, 6, 10, 15, 30
(2x2+3x-8)+(3x2-5x-7)
5x2-2x-15
Divide:
3x3+11x2-114x-80 / (3x+2)
x2+3x-40