Derive and fully simplify (don't expand)
f(x)=(3x^2+2)^5
30x(3x^2+2)^4
Derive
f(x)=sin(3x)
3cos(3x)
Derive
f(x)=ln(3x^2+5x)
(6x+5)/(3x^2+5x)
Derive
f(x)=e^(2x)
2e^(2x)
Given
h(x)=f(g(x))
h'(4)
28
Derive and fully simplify (No negative exponents)
sqrt(x^3+1)
(3x^2)/(2sqrt(x^3+1)
Derive
f(x)=cos(2x^2+lnx)
f'(x)=-sin(2x^2+lnx)(4x+1/x)
Derive
f(x)=ln(e^(2x)+4)
f'(x)=(2e^(2x))/(e^(2x)+4)
Derive
e^(3x^2+4x)
e^(3x^2+4x)(6x+4)
Given
h(x)=g(f(x))
h'(4)
56
Derive and fully simplify (No negative exponents)
f(x)=1/((x^2+4)^(3/2)
(-3x)/((x^2+4)^(5/2)
Derive
f(x)=tan(x^3)
f'(x)=sec^2(x^3)3x^2
Derive (simplify the trigonometry)
h(x)=ln(sin(x^2))
h'(x)=2xcot(x^2)
Derive
f(x)=e^(tan(2x)
2sec^2(x)e^(tan(2x))
Given
h(x)=f(g(x+2))
h'(1)
12
Determine the slope of the tangent of f(x) at x=1
f(x)=(3x^2+2)^2
60
Derive
h(x)=sin^2(2x+1)
4sin(2x+1)cos(2x+1)
Derive (no negative exponents)
p(x)=ln(x^3+sqrt(x))
p'(x)=(3x^2+1/(2sqrt(x)))/(x^3+sqrt(x)
Surprise! It's an anime clue
Name of Gon's dad from Hunter x Hunter
Ging Freecss
Given
h(x)=f(g(2x))
h'(2)
56
Find the equation of the tangent line of f(x) at the point where x=1. Keep it in point-slope form
f(x)=(2x^3+3x+1)^2
y-36=108(x-1)
Derive
f(x)=(x^2+1)(csc(3x))
f'(x)=2xcsc(3x)-3(x^2+1)csc(3x)cot(3x)
Derive (use logarithm properties, no quotient rule)
q(x)=ln((x^2+1)/(x^3+2))
(2x)/(x^2+1)-(3x^2)/(x^3+2)
Derive (simplify and factor)
h(x)=x^3e^(x^2)
h'(x)=e^(x^2)(3x^2+2x^4)
Given
h(x)=g(f(x/5))
h'(5)
2/5