4^((5*-2)/2)
1/4^5
1/1024
(\root[n](b+n))^n-(b+n)
0
(x^3/y^4)^(-1/3)
y^(4/3)/x
Write in Scientific notation
540000000
5.4*10^8
Simplify:
2sqrt50-4sqrt18-9sqrt32
-38sqrt2
-(16)^(5/4)
-32
((a+b)^-b/(a+b)^(-a))(a+b)
(a+b)^(a-b+1)
(-3sqrt(6xy^3))sqrt(6y)
-18y^2sqrtx
Write in scientific notation
0.000000032
3.2*10^-8
Simplify:
(2sqrta+sqrtb)(3sqrta-4sqrtb)
6a-5sqrt(ab)-4b
(2^-1/2^-2)^-2
1/4
((b+c)rootx(x))/(brootx(x)+crootx(x))^x
(b+c)^(1-x)x^((1-x)/x)
root3(108x^4y^8)
3xy^2root3(4xy^2)
Perform the calculation in scientific notation
(40,000,000*300,000)/0.3
4*10^13
Solve
sqrt(t^2+9t-1)=3
x=-10 &1
(2^-2/2^(-3/6))^(-4/3)/2
2
((w^-wb^zx)/(wb^-zx^z))^(-wbx)/(w^((wbx+bx)w)b^(-bxwz)x^(-wbx)
b^3x^(wbxz)
(4sqrt(8x)-sqrt(2y^4))(sqrt(8x)+3sqrt(2y^4))
32x+44y^2sqrtx-6y^4
Preform the calculation
4.5*(4,000,000)^(3/2)/(9,000,000)
2000
2*10^3
Solve (and check the answer!!!):
sqrt(x+1)-sqrt(2x)=-1
Only
x=8
((2^(2^2)/2^2)-(2^(2)/(2^2+2^2+2^2+2))^-1)^-1
2
((a^(b^c))^-b/root(b^c)(a^(b^c)))^-a
a^(a+ab^(1+c))
(4(R^4/R^(2+1))root3(24)+3Rroot3(3))R-2root3(81R^6)
5R^2root3(3)
Perform the calculation
((0.00004*300)/(0.00002))^(-3)
6*10^-6
The formula
S=sqrt(30Df)
is used to approximate the speed S, where D represents the length of the skid marks in feet and f represents the coefficient of friction for the road surface. Suppose that the coefficient of friction is 0.38. How far will a car skid, to the nearest foot, when the brakes are applied at 75 miles per hour?
75^2/(3*3.8)
or 493 feet