`4^((5*-2)/2)`
`1/4^5`
`1/1024`
`(\root[n](b+n))^n-(b+n)`
`0`
`(x^3/y^4)^(-1/3)`
`y^(4/3)/x`
Write in Scientific notation
`540000000`
`5.4*10^8`
Simplify:
`2sqrt50-4sqrt18-9sqrt32`
`-38sqrt2`
`-(16)^(5/4)`
`-32`
`((a+b)^-b/(a+b)^(-a))(a+b)`
`(a+b)^(a-b+1)`
`(-3sqrt(6xy^3))sqrt(6y)`
`-18y^2sqrtx`
Write in scientific notation
`0.000000032`
`3.2*10^-8`
Simplify:
`(2sqrta+sqrtb)(3sqrta-4sqrtb)`
`6a-5sqrt(ab)-4b`
`(2^-1/2^-2)^-2`
`1/4`
`((b+c)rootx(x))/(brootx(x)+crootx(x))^x`
`(b+c)^(1-x)x^((1-x)/x)`
`root3(108x^4y^8)`
`3xy^2root3(4xy^2)`
Perform the calculation in scientific notation
`(40,000,000*300,000)/0.3`
`4*10^13`
Solve
`sqrt(t^2+9t-1)=3`
`x=-10 &1`
`(2^-2/2^(-3/6))^(-4/3)/2`
`2`
`((w^-wb^zx)/(wb^-zx^z))^(-wbx)/(w^((wbx+bx)w)b^(-bxwz)x^(-wbx)`
`b^3x^(wbxz)`
`(4sqrt(8x)-sqrt(2y^4))(sqrt(8x)+3sqrt(2y^4))`
`32x+44y^2sqrtx-6y^4`
Preform the calculation
`4.5*(4,000,000)^(3/2)/(9,000,000)`
`2000`
`2*10^3`
Solve (and check the answer!!!):
`sqrt(x+1)-sqrt(2x)=-1`
Only
`x=8`
`((2^(2^2)/2^2)-(2^(2)/(2^2+2^2+2^2+2))^-1)^-1`
`2`
`((a^(b^c))^-b/root(b^c)(a^(b^c)))^-a`
`a^(a+ab^(1+c))`
`(4(R^4/R^(2+1))root3(24)+3Rroot3(3))R-2root3(81R^6)`
`5R^2root3(3)`
Perform the calculation
`((0.00004*300)/(0.00002))^(-3)`
`6*10^-6`
The formula
`S=sqrt(30Df)`
is used to approximate the speed S, where D represents the length of the skid marks in feet and f represents the coefficient of friction for the road surface. Suppose that the coefficient of friction is 0.38. How far will a car skid, to the nearest foot, when the brakes are applied at 75 miles per hour?
`75^2/(3*3.8)`
`or 493 feet`