Graph this inequality:
x > -3
open circle on -3 that goes to the right
Solve for the Inequality:
x + 6 > 2
What is:
x > -4
Solve for this inequality:
3x + 4 < 19
What is:
x < 5
Solve for this inequality:
-4 < t + 6 < 10
What is:
-10 < t < 4
Solve for this Absolute Value inequality:
|x| < 7
What is:
-7 < x < 7,
x > -7 and x < 7
Graph this inequality:
-1 > t
open circle on a negative 1 that goes to the left
Solve for this inequality:
p/(-3) < 6
What is:
p > -18
Solve for this inequality:
7 <= 2t - 5
What is:
t >= 6
Solve for this inequality:
12 > p + 7 > 5
What is:
-2 < p < 5
Solve for this Absolute Value inequality:
|r| - 7 < 15
What is:
-22 < r < 22
Graph this inequality
2(3-5) < k
open circle on -4 that goes to the right
Solve for this inequality:
-3 > (1/3)r
r < -9
Solve for this inequality:
(m+3) / 2 > -4
m > -11
Solve for this inequality:
7 < 2 - k OR 3.5 > 3 - k
k < -5 OR k > - 0.5
Solve for this Absolute Value inequality:
|x - 7| + 10 >= 12
What is:
x >= 9 or x <=5
Graph this inequality:
The temperature must be at least 72 degrees Fahrenheit.
closed circle on 72 that goes to the right
Solve for this inequality:
-0.4g > -1
What is:
g < 2.5
Solve for this inequality:
-4(2 - 5) > (-3)2 - h
What is:
h > -3
Solve for this inequality:
-2 < [4(3 - x)]/2 <2
What is:
2 < x < 4
Solve for this Absolute Value inequality:
[2|k| - 7] / -3 < -3
What is:
k > 8 or k < -8
Graph this inequality:
No more than 12 students were present
closed circle on 12 that goes to the left until zero, which will have an open circle
A senior class is selling lanyards as a fundraiser. The profit for each lanyard is $0.75. Write and solve an inequality to determine the number of lanyards the class must sell to make a profit of at least $250
What is:
0.75n >= 250; n >=333.33; they must sell at least 334 lanyards.
Solve for this inequality:
3.5t - 1.8 < 1.6t + 3.9
What is:
t < 3
DAILY DOUBLE!!!!!!!
Solve for this inequality:
2 > n + 3 > 5
What is:
No Solution
Solve for this Absolute Value inequality:
[-3 | 3j + 7 |] / 2 > -6
What is:
(-11/3) < j < -1
j > (-11/3) AND j < -1