HAs, VAs, Slants, None
Find that Value
Solve
Solve II
Applications p. 385 - p. 386
100

The asymptote for 

f(x) = e^x ?

y = 0

100

The min for 

f(x) = x^2 + 4x ?

- 4

100

4^x = 8 ?

3/2

100

5^(3x-1) = 125

4/3

100

To one decimal, #2, p. 385 (a) and (b).

7.5; base

200

The asymptote for 

f(x) = e^-x -2 ?

y = -2

200

The max for 

f(x) = -2x^2 + 4x - 5 ?

- 3

200

125^x = 25 ?

2/3

200

8^x = 1024

10/3

200

Answer in scientific notation to two decimal places:  #6 p. 385.

1.58 * 10^-3 to 1.58 * 10^-4

300

f(x) = (x^4 - 2x^3 - x^2 + 3)/(x^2 - 3x - 5

No HA; No slant; VA: x = (3 + - rad 29)/2

300

log (1000)

3

300

4 + 3 log(2x) = 16 ?

5000

300

4 - log(3-x) = 3

-7

300

To two decimal places, #10 (a) only p. 386.

5.86

400

The VA is x = 3.  What other asymptote is there for 

(x^2 -4x - 5)/(x- 3) ?

slant asymptote

400

8^(3/2)

16sqrt2

400

log [(x+2)(x-1)] = 1 ?

x = 3, -4 both are in domain as problem is written.

400

log x + log (x - 1) = log (4x)

5

400

Rounded to the nearest 100, #12 p. 386.

2500 times more intense

500

What are the equations for the two asymptotes for: 

f(x) = (x^2 - 4x - 5)/(x - 3)

VA: x = 3; Slant: y = x -1

500

ln e^7

7

500

4 - log(3 - x) = 3 ?

x = -7

500

Give both answers for 

2logx = log2 + log(3x - 4)

2,4

500

Give the answer as 

10^x W/m^2 for #18 p. 386.

10^-2.2 W/m^2

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