Density Curve
Normal Distribution
68-95-99.7 Rule and MORE
Calculating
Mix
100

What is the purpose of the density curve?

The density curve describes the overall pattern of a distribution and is intended to reflect the idealized shape of the population distribution.

100

What happen to the curve when the std ( sigma) gets bigger?

When σ is larger, the curve spreads out further and the area under the Normal curve is less concentrated about the mean.

100

How many percents of the observations fall within one standard deviation of the mean: (µ − σ, µ + σ).

68%

100

What percent of high school seniors meet this SAT requirement of a combined score of 980 or better?Given: N(µ = 1059, σ = 210).

0.648

100

What is the difference between a density curve and a histogram?

 A histogram is a plot of data obtained from a sample. A density curve is a reflection of data distribution under a curve

200
What is the total area under the curve?

1=100%

200

What does the STD σ control?

STD controls the variability of the variability or shape of a Normal curve

200

What is a z- score( standard score)?

It is the result of the process called standardizing? You take the observation - the mean and altogether divided by the std

200

In a course with 500 students, the midterm scores are N(µ = 70, σ = 10), want to find the proportion of students receive a score below 84.7. What is the result ?

92.92%

200

The distribution of heights of women aged 18 to 24 is approximately Normal with mean 63.7 inches and a standard deviatoin of 2.5 inches.

Q2. What percentage of young women have heights between 58.7 and 66.2 inches? i.e. P(58.7

81.5%

300

Two important properties of a density curve?

1) is always on or above the horizontal axis.

2) has an area of exactly 1=100% underneath it.

300

Where is the mean µ is located in the curve? Where is curve move when you change the mean without changing the standard deviation?

The mean µ is located at the center of the symmetric curve and is the same as the median.

 Changing µ without changing σ moves the Normal curve along the horizontal axis without changing its variability.

300

Where is the positive/negative  z score located at?

A positive z-score indicates the observation is above mean. 

A negative z-score indicates the observation is below the mean.

300

The distribution of heights of women aged 18 to 24 is approximately Normal with mean 63.7 inches and a standard deviatoin of 2.5 inches.

Q1. What percentage of young women have heights above 66.2 inches? i.e. P(women height > 66.2)?

16%

300

Describe the special Normal distribution?

The standard Normal distribution is the Normal distribution with mean µ = 0 and standard deviation σ = 1, denoted as N(0, 1).

400

where is mean and median in a density curve? 

- The median of a density curve is the equal-areas point, which divides the area under the curve in half.

 - The mean of a density curve is the balance point, or center of gravity, at which that curve would balance if it were made of solid material.

-The median and mean are the same for a symmetrical density curve. They both lie at the center of the curve.

400

What is the shape of a normal distribution?

symmetric, single-peaked, and bell-shaped

400

What is c-th percentile of a distribution means?

The c-th percentile of a distribution is a value such that c percent of the observations lie below it. That is, P(observations ≤ c-th percentile) = c ∈ [0, 1]. The median of any distribution is the 50% percentile.

400

The heights of all women aged 20 to 29 in the US are approximately Normal with µ = 64.1 and σ = 3.7 inches. The standardized height is

-1.11

400

What are the two determinant values of a normal curve?

A specific Normal curve is completely determined by its mean and standard deviation

500

Where is the mean of a skewed curve? 

The mean of a skewed surve is pulled away from the median in the direction of the long tail.

500

What is standardizing?

Mapping observations from N(µ, σ) units to N(0, 1) units.

500

How many percent of the observations fall within three standard deviations of the mean: (µ − 3σ, µ + 3σ).

99.7%

500

How high must a student score in order to be in the top 10% (90% percentile) of the distribution? i.e. find x0 so P(scores ≥ x0) = 10%

Given: SAT reading scores for a recent year are distributed according to an N(µ = 531, σ = 104) distribution.

x0 = 664.12 

500

If a distribution is skewed to the left? Where is the mean and the median?

The mean is less than the median.

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