solubility
acids/bases
molarity
titration
redox
100

True or False:

Acetate is always soluble no matter what it is paired with.

true 

100

what is an acid?

acids produce or increase the concentration of the hydrogen ion in a solution

100

what are the units for molarity? 

moles/ liter solution 

100
what is the keyword in titration problems?

neutralization

100

What is the oxidation number of the phosphorus in HPO3?

+5 

200

Cl-, Br-, and I- are always water-soluble except when they are paired with...

Ag+, Pb2+, Hg2+, and Hg22+

200

what is a base?

bases are substances that increase the OH- ion concentration in a solution. 

200

How many grams of Na2SO4 are required to make exactly 0.250L of 55mM Na2SO4?

55mM = .055M

.055M * (.250L)= .01375 moles

0.01375 * ( 142g/ 1 mole) = 1.95g Na2SO4

200

It takes 83 mL of a 0.45 M NaOH solution to neutralize 235 mL of an HCl solution. What is the concentration of the HCl solution?

.16 M HCl

200

what is the oxidation number of Mn in MnO4-?

+7

300

complete the following reaction. then write the complete ionic equation and the net ionic equation. 

NH4Br(aq) + Pb(C2H3O2)2(aq) →

2NH4Br(aq) + Pb(C2H3O2)2(aq) → 2NH4C2H3O2(aq) + PbBr2(s) 

Complete: 2NH4+(aq) + 2Br(aq) + Pb2+(aq) + 2C2H3O2(aq) → 2NH4+(aq) + 2C2H3O2(aq) + PbBr2(s) 

Net: 2Br(aq) + Pb2+(aq) → PbBr2(s) 

300

H3PO4+ 3KOH→ 3H2O+ K3PO4 is an example of...

a neutralization reaction 

acid + base → water + salts

300

How much 0.05 M HCl solution can be made by diluting 250 mL of 10 M HCl?

M1V1 = M2V2
(10 M)(250 mL) = (0.05 M) x 

x = 50,000 mL

300

It takes 38 mL of 0.75 M NaOH solution to completely neutralize 155 mL of a sulfuric acid solution (H2SO4). What is the concentration of the H2SO4 solution?

.092 M H2SO4

300

What are the oxidizing agent and the reducing agent in the following...

Pb(OH)42- + ClO- --> Cl- + PbO2

oxidizing: ClO-

reducing: Pb(OH)42-

400

complete the following reaction, write the complete ionic equation, and write the net ionic equation. 

2K3PO4(aq) + 3Cd(C2H3O2)2(aq) →

2K3PO4(aq) + 3Cd(C2H3O2)2(aq) → 6KC2H3O2(aq) + Cd3(PO4)2(s) 

Complete: 6K+(aq) + 2PO43−(aq) + 3Cd2+(aq) + 6C2H3O2(aq)→ 6K+(aq) + 6C2H3O2(aq) + Cd3(PO4)2(s) 

Net: 2PO43−(aq) + 3Cd2+(aq) → Cd3(PO4)2(s) 

400

what are your strong bases? 

group 1 hydroxides and group 2 hydroxides 

400

I have 345 mL of a 1.5 M NaCl solution. If I boil the water until the volume of the solution is 250 mL, what will the molarity of the solution be?

M1V1 = M2V2
(1.5 M)(345 mL) = x (250 mL)

 x = 2.07 M

400

It takes 12.5 mL of a 0.30 M HCl solution to neutralize 285 mL of NaOH solution. What is the concentration of the NaOH solution?

.013 M NaOH

400

Balance the following in acidic solution... 

PH3 + I2 ---> H3PO2 - + I -

4H2O + 2PH3 + 3I2---> 2H3PO2- + 6I- + 8H+

500

Write the soluble guidelines tables for water-soluble and water-insoluble.

Water Soluble:

Always soluble                          Except when paired with:

NO3-, C2H3O2-, ClO4-

Cl-, Br-, I-                                Ag+, Pb 2+, Hg 2+, Hg22+

SO4                                Ca 2+, Ba 2+, Sr 2+, Pb 2+, Ag+, Hg22+


Water-insoluble:

Always insoluble                                      Except

S 2-, OH-                          NH4+, Ca 2+, Sr 2+, Ba 2+, group one

CO32-, PO43-                                 NH4+, group one


500

list and name all of the strong acids you need to know for your exam. 

HCl (hydrochloric acid) 

HBr (hydrobromic acid)

H2SO4 (sulfuric acid)

HNO3 (nitric acid) 

HClO3 (chloric acid) 

HClO4 (perchloric acid)

500

how do you make an acid solution?

Start with a 500ml flask, add half of the water (not up to the line on the flask), put the lid on and shake flask, take lid off, add water up to the line, put the lid on, do 20 inversions. 

500

Calculate the mass of the percipitate fomred when we mix 1.25 L of 0.05M Pb(NO3)2 and 2 L of 0.0250M Na2SO4. 

15.2 g PbSO4

500

Balance the following in basic Solution

Zn  ===>  Zn(OH)4 2-  +  H2

Zn  ===>  Zn(OH)4 2-  +  H2

4H2O  +  Zn   ===>   Zn(OH)4 2-  +  4H+  +  2e

2 e  +  2 H2O   ===>   H2  +  2 OH -

2 OH +  Zn  +  2 H2O   ===>   Zn(OH)4 2-  + H2


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