Multiply It!
4 x 23
4 x 23 = 92
Solve 32 x 4
32 x 4 = 128
1.) Break down each number by its place value:
32 = 30+ 2
4 stays 4
2.) Multiply each part of the 1st number by each part of the 2nd number:
30 x 4 = 120
2 x 4 = 8
3.) Add all of the partial products together to find the total:
120 + 8 = 128
Solve 12 x 3
12 x 3 = 36
1.) Break down each number by its place value:
12 = 10 + 2
3 stays 3
2.) Multiply each part of the 1st number by each part of the 2nd number:
10 x 3 = 30
2 x 3 = 6
3.) Add all of the partial products together to find the total:
30 + 6 = 36
21 x 12
21 x 12 = 252
A teacher has 12 boxes of pencils. Each box contains 4 pencils. How many pencils does the teacher have altogether?
48 because 12 boxes x 4 pencils each = 48
7 x 36
7 x 36 = 252
Solve 23 x 14
23 x 14 = 322
1.) Break down each number by its place value:
23 = 20+ 3
14 = 10 + 4
2.) Multiply each part of the 1st number by each part of the 2nd number:
20 x 10 = 200
3 x 10 = 30
20 x 4 = 80
3 x 4 = 12
3.) Add all of the partial products together to find the total:
200 + 30 + 80 + 12 = 322
Solve 15 x 12
15 x 12 = 180
1.) Break down each number by its place value:
15 = 10+ 5
12 = 10 + 2
2.) Multiply each part of the 1st number by each part of the 2nd number:
10 x 10 = 100
5 x 10 = 50
10 x 2 = 20
5 x 2 = 10
3.) Add all of the partial products together to find the total:
100 + 50 + 20 + 10 = 180
34 x 16
34 x 16 = 544
An auditorium has 18 rows of chairs. Each row contains 12 chairs. How many chairs are there in all?
216 because 18 rows x 12 chairs each = 216
8 x 47
8 x 47 = 376
Solve 46 x 23
46 x 23 = 1,058
1.) Break down each number by its place value:
46 = 40+ 6
23 = 20 + 3
2.) Multiply each part of the 1st number by each part of the 2nd number:
40 x 20 = 800
6 x 20 = 120
40 x 3 = 120
6 x 3 = 18
3.) Add all of the partial products together to find the total:
800 + 120 + 120 + 18 = 1,058
Solve 24 x 13
24 x 13 = 312
1.) Break down each number by its place value:
24 = 20+ 4
13 = 10 + 3
2.) Multiply each part of the 1st number by each part of the 2nd number:
20 x 10 = 200
4 x 10 = 40
20 x 3 = 60
4 x 3 = 12
3.) Add all of the partial products together to find the total:
200 + 40 + 60 + 12 = 312
57 x 24
57 x 24 = 1,368
A grocery store receives 24 bags of apples. Each bag contains 16 apples. How many apples did the store receive?
384 because 24 bags x 16 apples each = 384
9 x 68
9 x 68 = 612
Find the product of 37 x 24
37 x 24 = 888
1.) Break down each number by its place value:
37 = 30+ 7
24 = 20 + 4
2.) Multiply each part of the 1st number by each part of the 2nd number:
30 x 20 = 600
7 x 20 = 140
30 x 4 = 120
7 x 4 = 28
3.) Add all of the partial products together to find the total:
600 + 140 + 120 + 28 = 888
Solve 32 x 21
32 x 21 = 672
1.) Break down each number by its place value:
32 = 30+ 2
21 = 20 + 1
2.) Multiply each part of the 1st number by each part of the 2nd number:
30 x 20 = 600
2 x 20 = 40
30 x 1 = 30
2 x 1 = 2
3.) Add all of the partial products together to find the total:
600 + 40 + 30 + 2 = 672
68 x 35
68 x 35 = 2,380
A school sells 36 tickets for each of its 14 performances. How many tickets could the school sell if every performance sells out?
504 because 36 tickets x 14 performances = 504
6 x 89
6 x 89 = 534
Solve 58 x 36
58 x 36 = 2,088
1.) Break down each number by its place value:
58 = 50+ 8
36 = 30 + 6
2.) Multiply each part of the 1st number by each part of the 2nd number:
50 x 30 = 1500
8 x 30 = 240
50 x 6 = 300
8 x 6 = 48
3.) Add all of the partial products together to find the total:
1500 + 240 + 300 + 48 = 2,088
Solve 46 x 28
46 x 28 = 1,288
1.) Break down each number by its place value:
46 = 40+ 6
28 = 20 + 8
2.) Multiply each part of the 1st number by each part of the 2nd number:
40 x 20 = 800
6 x 20 = 120
40 x 8 = 320
6 x 8 = 48
3.) Add all of the partial products together to find the total:
800 + 120 + 320 + 48 = 1,288
79 x 46
79 x 46 = 3,634
A school has 28 classrooms. Each classroom has 24 students. How many students go to the school altogether?
672 because 28 classrooms x 24 students each = 672