% problems
M1V1=M2V2
C1V1=C2V2
Acid/Base
weak acid/base
Naming
Turning to Formula
100

How many g of KCl and water are present in 225g of 8.00% m/m solution of KCl?

18 g of KCl and 207 g of water

100

Calculate the volume in mL of 3.5% solution prepared by diluting 45 mL of 7.0% KOH solution

90mL

100

HCl + H2O -> H3O+ + Cl-

Acid = HCl and Base = H2O

100

Cu(OH)2

Copper (II) Hydroxide

100

Nitric Acid

HNO3

200

How many mL of 5.46% v/v propyl alcohol solution are needed to get 23.6 mL of propyl added?

432 mL of solution

200

What is the final concentration of a solution prepared by diluting 50.0 mL of 8.00% m/v solution of NaOH to 200. mL?

Final Concentration is 2.00%

200

NH3 + H2O <-> NH4+ +OH-

Acid: H2O and Base: NH3 

200

HBr

Hydrobromic Acid

200

Aluminum Hydroxide

Al(OH)3

300

Calculate %m/V for a 750mL CaCl2 solution prepared by dissolving 74.3 g of CaCl2

9,91% m/v CaCl2

300

Calculate initial molarity if 75 mL of initial solution is diluted to 0.450 L with molarity of 2.15 M

Initial molarity is 12.9 M 

300

HCO2- + H2O -> HCOOH + OH-

Acid: H2O and Base: HCO2-

300

H3PO4

Phosphic Acid

300

Carbonic Acid

H2(CO3)

400

Calculate 40.% v/v alcohol solution. How many mL of alcohol are present in a 0.750L bottle of brandy?

300 mL

400

How many liters of water and a 24% stock solution of the chemical are needed to dilute down to form 135 L of a 7% solution

40 L of water

400

H2PO4- + HCO3- -> H2CO+ HPO4-2

Acid: H2PO4- and Base: HCO3-

400

Fe(OH)3

Iron (III) Hydroxide

400

Zinc Hydroxide

Zn(OH)2

500

How many grams of water are present in the 5.21% m/m solution of KCl made by dissolving 16.4g KCl?

314 grams of KCl and 298 grams of water

500

You have a stock solution of concentration 5.0 M, but your patient needs a solution with a concentration of 2.5 M. How many mL of the stock solution should you use to create 500. mL of the 2.5M solution?

250 ml of stock solution

500

HCl + NH3 -> NH4+ + Cl-

Acid: HCl and Base: NH3

500

HI

Hydroiodic acid

500

Hydrobromic acid

HBr

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