NH4+ + OH- --> NH3 + H2O
1,1,1,1
The amount in grams of Fe produced from 6.79E23 molecules of CO in the equation FeO + CO --> Fe + CO2
What is 63.0 g?
Molarity of H+ in 0.75 M H2SO4 solution
1.5 M
molarity of 1L solution with 2.5 moles HCl
2.5 M
CH4 + O2 --> H2O + CO2
1,2,2,1
The amount in moles of C3H8O required to produce 77 g H2O through the chemical equation,
2C3H8O + 9O2 --> 8H2O + 6CO2
What is 1.07 moles of C3H8O?
Steps and equipment required to make a dilution
add the appropriate amount of solute to a volumetric flask
add some water, and swirl, add more water and swirl
continue until the volumetric flask is filled to the line
moles of NaCl in 65 ml of 3.8 M NaCl solution
247 moles
FeCl3 + NaOH --> Fe(OH)3 + NaCl
1,3,1,3
2C2H2 + 5O2 --> 4CO2 + 2H2O
Grams of water produced from combusting 113g of C2H2
78.2g H2O
You have 1 L of 6 M HCl stock solution and need to make 150 ml of a 2.5 M solution. How much stock solution do you need to use
62.5 ml
volume in ml of 7.2 NaCl M that has 350 g NaCl
831 ml
NaHCO3 + H2SO4 --> Na2SO4 + H2O + CO2
2,1,1,2,2
2 NaOH + H2SO4 --> 2 H2O + Na2SO4
Moles of Na2SO4 formed from 200g NaOH
1.25 moles Na2SO4
Molarity of 174 ml of a solution with 138 g of HCl
21.7 M
Moles NaOH in 350 ml of 7.5 M NaOH solution
2.63 moles
C2H2 + O2 --> CO2 + H2O
2,5,4,2
Pb(SO4)2 + 4 LiNO3 --> Pb(NO3)4 + 2 Li2SO4
Grams of LiNO3 required to make 250g Li2SO4
314 g LiNO3
You use 245 ml of 2.5 M NaOH stock solution to create how much 0.95 M solution
645 ml
volume, in ml, of 1.68 M H2SO4 solution that has 73 g H2SO4
443 ml