Balance: H2 + NO → H2O + N2
2 H2 + 2 NO → 2 H2O + N2
Br2 + 2 NH4Cl → 2 NH4Br + Cl2
single replacement
6.02 x 1023
2 FeCl2 + Cl2 → 2 FeCl3
Given: 75.18 grams FeCl2 reacted
Wanted: grams of Cl2 reacted?
21.03 grams Cl2
6Na + Fe2O3 --> 3Na2O + 2Fe If you are provided 200g of sodium and 250 grams of iron(III) oxide, which substance is the limiting reactant?
sodium
Balance: Cu(NO3)2 + KOH → Cu(OH)2 + KNO3
Cu(NO3)2 + 2 KOH → Cu(OH)2 + 2 KNO3
2 Ca + O2 → 2 CaO
combination
What is molar mass and how is it found?
The mass of one mole of a substance, add together the masses of each element from the chemical formula
NH4OH → NH3 + H2O
Given: 412.19 grams NH4OH reacted
Wanted: grams of H2O produced?
211.89 grams H2O
6Na + Fe2O3 --> 3Na2O + 2Fe If you are provided 200g of sodium and 250 grams of iron(III) oxide, determine the amount of solid iron produced.
162 g Fe
Balance: Al2O3 + C → Al + CO2
2 Al2O3 + 3 C → 4 Al + 3 CO2
Cu(NO3)2 + 2 KOH → Cu(OH)2 + 2 KNO3
double replacement
Determine empirical formula of: 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen
CH2O
2 Al + 3 H2SO4 → Al2(SO4)3 + 3 H2
Given: 1.0186 moles H2SO4 reacted
Wanted: moles of Al2(SO4)3 produced?
0.33953 moles Al2(SO4)3
6Na + Fe2O3 --> 3Na2O + 2Fe If you are provided 200g of sodium and 250 grams of iron(III) oxide, how much of the iron(III) oxide was left over?
18 g
Balance: C6H10O5 + O2 → CO2 + H2O
C6H10O5 + 6 O2 → 6 CO2 + 5 H2O
4 KNO3 → 2 K2O + 2 N2 + 5 O2
decomposition
Empirical formula: CH2O
Formula mass 180 g/mol
C6H12O6
4 Si2H3 + 11 O2 → 8 SiO2 + 6 H2O
Given: 8.8 × 1022 particles SiO2 produced, 1.6 × 1023 particles of O2 reacted
Wanted: % yield?
Correct answer is 76%
100% yield would give 1.2 × 1023 particles SiO2
If you have 3.50 moles of hydrogen and 5.00 moles of nitrogen to produce ammonia, how much nitrogen is used up? 3H2 + N2 --> 2NH3
32.7 g
Balance: C5H10O5 + O2 → CO2 + H2O
C5H10O5 + 5 O2 → 5 CO2 + 5 H2O
2 C6H6 + 15 O2 → 12 CO2 + 6 H2O
combustion
When is mass in grams the same as mass in amu?
When there is one mole of a substance
F2 + 2 KCl → 2 KF + Cl2
Given: 1.6 × 1025 particles F2 reacted at 67% yield
Wanted: particles of KF produced?
Correct answer is 2.1 × 1025 particles KF
• 100% yield would give 3.2 × 1025 particles KF
If you have 3.50 moles of hydrogen and 5.00 moles of nitrogen to produce ammonia, how much nitrogen is left over? 3H2 + N2 --> 2NH3
107.3 g