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Aluminum bromide and sodium hydroxide react to form aluminum hydroxide and sodium bromide
How many moles of aluminum hydroxide may be formed from 4.65 moles of sodium hydroxide?
AlBr3 + 3 NaOH ---> Al(OH)3 + 3 NaBr
4.65mol NaOH * (1mol Al(OH)3 / 3mol NaOH) = 1.55mol AL(OH)3