400
A 4.00L reaction vessel contained 0.140mol of H2, 0.300mol of Br2, and 0.357mol of HBr. Assuming that the substances are already at equilibrium, write an equilibrium constant expression and find the value of Kc.
H2(g) + Br2(g) <---> 2HBr(g)
What is
H2= 0.140mol =0.035M Kc=[HBr]^2
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4.00 [H2][Br2]
Br2=0.300mol =0.075M Kc =(0.089)^2
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4.00L (0.035)(0.075)
HBr=0.357mol =0.089M Kc= 3.02
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4.00L