Empirical & Molecular Formula
Mole Map
Molar Mass
Percent Composition
Dimensional Analysis
100

Emirical formula Haiku

Percentage to mass

Mass to mole, divide by small

Multiply til whole

100

How do you get from 

Mass to Moles

Particles to Moles

Volume of Gas to Moles

1.00 mol/Molar Mass

1mol/6.02x10^23 particles

1mol/22.4L

100

What is Molar Mass

the mass (in grams) of 1 mole off any substance.

100

What is Percent Compisition

The percentage by mass of each element in a compound

100

What is the first thing you do in any mole problem

Where your going on the mole map

200

What is the molecular formula

Its  the same as its experimentally determined by the empirical formula, or it is a simple whole-number multiple of its empirical formula.

200

How do you get from 

Moles to Mass

Moles to Particles

Moles to Volume of Gas

Molar Mass/1.00 mol

6.02x1023 particles/1mol

22.4L/Mol

200

Find the Molar Mass of H2O

H = (2 x 1.01 g/mol) = 2.02 g/mol

 O = (1 x 16.00 g/mol) = 16.00 g/mol

The total Molar Mass = 18.02g/mol

200

What is the percent composition formula

Percent= Part/Whole x 100%

200

Dimensional analysis is a versatile and powerful problem-solving technique.

True or False

True

300

What are the three steps to a molecular formula

1. Determine the empirical Formula

2. Divide the molar mass of the compound by the empirical formula mass

3. Multiply all subscripts in the empirical formula by this number

300

What volume would 0.600 moles of SO2 gas occupy at STP?

0.600 mol SO2 x 22.4 L/1 mol SO2

= 13.4 L SO2

300

What is the Molar Mass of Fe2

55.85g + 55.85g

111.7g

300

What are the 3 step to a percent composition problem

Step 1: Determine the molar mass of the compound.

Step 2: Divide the total mass of each element in the compound by the molar mass calculated in step 1 and multiply each by 100. Round to the nearest 0.01%.

Step 3: Check to see that the %’s add up to 100.

300

Purpose of Dimensional Analysis

To easily and correctly convert from one unit to another.

400

Calculate the molecular formula of a compound whose molar mass is 92.0 g/mol and empirical formula is NO2

empirical formula of NO2 = 14.01 + (2 x 16.00).     = 46.01 g/mol

92.00g/mol/46.01g/mol

400

How many molecules of NO2 are in 0.330 moles of NO2?

0.330 mol NO2 x 6.02 x 1023 molecules/1 mol NO2

= 1.99 x 1023 molecules NO2

400

What is the molar mass PbSO4

(1 x 207.20g) + (1 x 32.07g) + (4 x 16.00g)

=303.27 g/mol

400

In a typical day, you spend 27% of your time on your phone. How many hours is this?

24 hours x 27/100= 6.48hours

400

How many minutes are there in two days?

1 day -24 hr

1hr- 60min

2 x 24 x 60/1

=2880 minutes

500

Determine empirical formula for a compound that is found to contain 40.0% carbon, 6.67% hydrogen, and 53.3% oxygen. The compound’s molar mass is 120.0 g/mol.

Double Jeopardy option πŸ˜±πŸ˜„πŸ˜πŸ˜„πŸ‘πŸΌπŸ’΅πŸ’΅πŸ’΅πŸ’΅πŸ’΅πŸ’΅πŸ’΅πŸ’ΈπŸ’΅πŸ’ΈπŸ’ΈπŸ’΅πŸ’ΈπŸ›’πŸ’΅πŸ’ΈπŸ’ΈπŸ’ΈπŸ’°πŸ’°πŸ’°πŸ’ŽπŸ’ŽπŸͺ™πŸ’° 

Determine molecular formula for a compound that is found to contain 40.0% carbon, 6.67% hydrogen, and 53.3% oxygen. The compound’s molar mass is 120.0 g/mol.

C 3.33    H 6.60.     O3.33

CH2O


Answer to double Jeopardy

Empirical Formula=

of CH2O = 12.01 + (2 x 1.01) + 16.00 = 30.03 g/mol

120.0 g/mol/30.03 g/mol

=4

(CH2O)4  =(C4H8O4)

500

 What is the volume of 7.87 x 1024 molecules of carbon dioxide at STP?



7.87 x 1024 x 1molCo2/6.02 x 1023 x 22.4l/1mol Co2

=(7.87 x 1024 x 1 x 22.4L)/(6.02 x 1023 x 1)

293l CO2


500

What is the Molar mass of AgNo3

(1x107.87g/mol)= 107.87g/mol

(1x14.01g/mol)= 14.01g/mol

(3x16.00g/mol)= 48.00g/mol

169.88

500

Percent Composition of

silver nitrate, AgNO3

(1x107.87g/mol)= 107.87g/mol

(1x14.01g/mol)= 14.01g/mol

(3x16.00g/mol)= 48.00g/mol

169.88

Ag=(107.87/169.88) x 100= 63.50%

N=(14.01/169.88) x 100=8.25%

O=(48.00/169.88) x 100=28.25%

500

How many days is 5000 minutes?

60min-1hr

24hr- 1 day

3.5 days

500/1 x 1 /60 x 1 /24 = 3.4722

always round up to a whole

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