500
According to Bohr's emission spectra... electron A which transitions from n=4 to n=2 differs from electron B which transitions from n=3 to n=2 because electron A emits (less/more) energy and therefore has a (lower/higher) frequency and a (shorter/longer) wavelength
What is "more energy, higher frequency, shorter wavelength" ~ Reasoning: you need to understand the relationships between the three variables to get this problem correct... energy and frequency are directly proportional while frequency and wavelength are indirectly proportional