Polar Bonds and Molecules
Intermolecular Forces
Enthalpy and Energy Diagrams
Hess' Law
Standard Enthalpies of Formation
100
Is the C to H bond polar?

No

100

What is the strongest intermolecular force?

ion-dipole

100

What is enthalpy?

energy as heat

100

What CAN change according to Hess' Law

the reaction pathway

100

What are standard conditions?

P = 1 atm

T = 25ºC or 298.15 K

200

Is the bond between H and Br polar?

Yes

200

Which intermolecular force is present between all molecules?

dispersion forces

200

Is baking bread an exothermic or endothermic reaction?

Endothermic
200

What CANNOT change according to Hess' Law?

The change in enthalpy.

200

What is the standard enthalpy of formation of solid copper?

0 kJ/mol

300

Is water a polar molecule?

Yes

300

What is the strongest IMF NH3 could form with itself?

hydrogen bonds

300

When you bake bread, what is the system?

the bread

300

Determine the correct modification to the first reaction given the following problem:

Calculate the enthalpy change for the reaction P4O6 + 2O2 -> P4O10 given the following enthalpies of reaction:

1)  P4 + 3O2 -> P4O6   ∆H = -1640.1 kJ/mol

2)  P4 + 5O2 -> P4O10   ∆H = -2940.1 kJ/mol

Flip the reaction and change the sign of ∆H

300

Which standard enthalpies of formations do you add together first when trying to find the standard enthalpy of a reaction?

products

400

Is CF4 a polar molecule?

No

400

Why can you add water to the top of a penny without the water spilling over?

The water adheres to itself with hydrogen bonds so it has surface tension that takes more energy to break.

400

What can you say about a reaction that has a ∆H=-87 kJ/mol?

it is exothermic

400

How does a catalyst affect a reaction? Relate this back to Hess' Law.

A catalyst lowers the activation energy, which changes the pathway of the reaction but does not affect the ∆H as per Hess' Law

400

What is the standard enthalpy of reaction for the following: 

C4H8(g) --> 4C(s) + 4H2(g)

if ∆Hºf(C4H8) = -0.63 kJ/mol.

0.63 kJ/mol

500

Why is C2H8N nonpolar?

It is a symmetrical molecule.

500

What is the strongest IMF that could form between Ca2+ and CH4?

dispersion forces

500

Describe or draw an exothermic energy diagram. Label all parts.

Two axes labeled "energy" (y-axis) and "reaction coordinate" (x-axis). Energy of reactants on the left, relatively high up. A hump after the energy of reactants labeled at the top of the hump as "energy of transition state" and at the end as "energy of products" (this should be lower than the energy of reactants). The distance between the energy of reactants and the energy of transition state labelled "activation energy." The distance between the energy of reactants and the energy of the products labelled "∆H."

500

Where does the solution go WRONG in the following:

Example #1: Calculate the value of ΔH° for the following reaction:

P4O10(s) + 6PCl5(g) ---> 10Cl3PO(g)

using the following four equations:

(a) P4(s) + 6Cl2(g) ---> 4PCl3(g)ΔH° = −1225.6 kJ

(b) P4(s) + 5O2(g) ---> P4O10(s)ΔH° = −2967.3 kJ

(c) PCl3(g) + Cl2(g) ---> PCl5(g)ΔH° = −84.2 kJ

(d) PCl3(g) + 1⁄2O2(g) ---> Cl3PO(g)ΔH° = −285.7 kJ

Solution:

(a) P4(s) + 6Cl2(g) ---> 4PCl3(g)ΔH° = −1225.6 kJ

(b) P4O10(s) ---> P4(s) + 5O2(g)ΔH° = –2967.3 kJ

(c) 6PCl5(g) ---> 6PCl3(g) + 6Cl2(g)ΔH° = +505.2 kJ

(d) 10PCl3(g) + 5O2(g) ---> 10Cl3PO(g)ΔH° = −2857 kJ

6) The ΔH° values added together:

−1225.6 kJ + (–2967.3 kJ) + (+505.2 kJ) + (−2857 kJ) = −6544.7 kJ

7) The answer:

P4O10(s) + 6PCl5(g) ---> 10Cl3PO(g)ΔH° = −6544.7 kJ

Equation b is flipped, but the ∆H does not change signs
500

What is the standard enthalpy of reaction for 4FeO(s) + O2(g) -> 2Fe2O3(s)?

-560.4 kJ/mol

M
e
n
u