Consider the following rxn:
CO + 2 H2 <--> CH3OH
A reaction mixture at 1500 degrees Celsius initially contains [CO]= 0.98 M and [H2]=1.43 M. At equilibrium, the [CO] is .88 M. What is the value of Kc?
Kc=.075
HCl
LiOH
HF
Cl-
LiOH2+
F-
HBr
HBr+H2O <--> Br- + H3O+
Heat+ Br2 <--> 2 Br-
Increase Br2
Remove Br-
Right
Right
HCl
LiOH
SA
SB
Given the rxn: CH4 <--> C2H + 2 CH3
The equilibrium concentrations are as follows:
CH4= 3.52 M
C2H= 4.5 M
CH3= 3.44 M
What is the Kc?
Kc=15.12
NH3
HI
HBr
NH4+
I-
Br-
LiOH
LiOH + H2O <--> LiOH2+ + OH-
Heat+ Br2(g) <--> 2 Br-(g)
Remove Br2
Increase Br-
Left
Left
HI
KOH
NH3
SA
SB
WB
The Kc for a reaction is 23.5. What would happen to the Kc value if the reaction is flipped and is multiplied by 3?
Kc=7.7x10^-5
Ba(OH)2
CH3NH2
HCN
HBa(OH)2+
CH3NH3+
CN-
H2SO4
H2SO4 + H2O <--> HSO4- + H3O+
Heat+ Br2(g) <--> 2 Br-(g)
Increase temperature
Decrease Heat
Right
Left
HF
CsOH
Ca(OH)2
WA
SB
WB
Given the reaction:
7 CH4 <--> 18 O2
and the concentrations at initial:
CH4= 0.2M
O2= 0.2M
What's the Q value?
2.05 x10 ^-8
HOH
H3O+
OH-
H+ or OH-
H3O+
H3O+ + H2O <--> H3O+ + H2O
Heat+ Br2(g) <--> 2 Br-(g)
Increasing Pressure
Increasing Volume
Left
Right
Cl-
H2O
WB
WA or WB
Consider the following reaction: S2O2 <--> 2SO2
Kc= 23.6
A rxn mixture initially contains [SO2]=13.1
Find the equilibrium concentrations of each product and reactant
[S2O2]=4.12
[SO2]=4.86
CH3CH2COOH
H2SO4
F-
CH3CH2COO-
HSO4-
HF
CH3CH2CH2CH2CH2CH2COOH
CH3CH2CH2CH2CH2CH2COOH + H2O <--> H3O+ + CH3CH2CH2CH2CH2CH2COO-
Heat+ Br2 <--> 2 Br-
Adding Krypton
Adding H+
Nothing
Right
HClO4
H2SO4
Ba(OH)2
CH3COOH
SA
SA
SB
WA