A circle in the xy-plane has its center at (44,-34) and radius √3. What is the equation of the circle?
(x-44)^2+(y+34)^2=3
A circle S passes through the point (0,1) and is orthogonal to the circles (x-1)^2+y^2=16 and x^2+y^2=1. Find the radius and the center of the circle
Radius= 7
Center= (-7,1)
The circle passing through the point (-1,0) and touching the y-axis at (0,2) also passes through the point..
(a) (-3/2,0)
(b) (-5/2,2)
(c) (-3/2,5/2)
(d) (-4,0)
(d) (-4,0)
A circle has centre A. The points C(0,4) and D (10,4) lie on the diameter of the circle.
(a) Find the coordinates of A.
(b) Find the equation of the circle.
(a): A(5,4)
(b): (x-5)^2+(y-4)^2=25
The points of intersection of the line 4x-3y-10=0 and the circle x^2+y^2-2x+4y-20=0 are
(4,2) and (-2,-6)
Find the centre of the circle inscribed in the square formed by the lines x^2-8x+12=0 and y^2-14y+45=0
(4,7)
A circle in the xy-plane has its center at (7,14). If the point (7,34) lies on a circle, what is the equation of the circle.
(x-7)^2+(y-14)^2=400
Consider a circle with a center at (2,-1) and a tangent line with an equation of 3x-4y+7=0. Determine the equation of the circle
(x-2)^2+(y+1)^2=16/9
If the tangent at the point P on the circle is x^2+y^2+6x+6y=2 meets a straight line 5x-2y+6=0 at a point Q on the y-axis, then the length of PQ is
5
A circle in the xy-plane has the equation 2x^2+2y^2-8x-5y-55/8=0. What is the diameter of the circle?
6 units.
What is the maximum value of y on the circumference of the circle defined by the equation x^2+y^2+6x-10y-47=0
14
Find where the circle (x−4)²+(y−6)²=32 meets the x-axis.
It does not intercept the x-axis
Let the tangents drawn from the origin to the circle, x^2+y^2-8x-4y+16=0 touch it at points A and B. Then (AB)^2 is equal to
64/5
Write the standard form of the equation of the circle that passes through the points (-2, 3), (6, -5), and (0, 7). Once the equation is in standard form, what are the values of the D, E and F
The solution to the system is D = -10, E = -4, and F = -21.
Find where the circle (x−2)² + (y−1)² =68 meets the x-axis.
(2-√67,0) and (2+√67,0)