i2 =
-1
(2+3i) + (1+4i)
3+7i
(4+5i) − (2+3i)
2+2i
(2+3i) × (1+i)
-1+5i
4+3i
____
1+i
7 i
_ - _
2 2
3i2 =
-3
(5+0i) + (−3+2i)
2+2i
(7+2i) − (3+4i)
4-2i
(4+i) × (2−3i)
11-10i
5-i
____
2+3i
7 17i
__ - ___
13 13
5i4 =
5
(7−5i) + (−2+6i)
5+i
(6−3i) − (2+5i)
4 - 8i
(3+2i) × (1−i)
5-i
6+2i
____
3-i
8 6i
_ + __
5 5
True or false: i3 = i
False. The correct answer is -i
(3+4i) + (−7−2i) + (5−3i)
1-i
(5+4i) − (3−6i) − (2+7i)
3i
(5−2i) × (3+4i)
23+14i
7+4i
____
2-5i
-6 43i
__ + ___
29 29
i102 =
(4−6i) + (2+9i) + (−3+5i) + (−7−8i)
-4
(8−5i) − (4+3i) − (7−9i) + (2+6i)
-1+7i
(2+5i) × (1−3i) × (4+i)
69+13i
(3+4i) (5-i)
_____ x ____
(1-2i) (2+i)
-23
___ + 5i
5