Equation Station
Aren't You Spontaneous?
Mr. Hess' Mess
Entropy? Who is He?
It's Getting Hot in Here (specific heat)
100

What is the equation for specific heat?

q = mcΔT

100

What must ΔH and ΔS be in a combustion reaction?  Is this spontaneous?

-, +, always spontaneous

100

For the reaction

H2(g)+1/2 O2(g)→H2O(l)

the enthalpy change is –285.8 kJ.
If 2 moles of water are produced, what is ΔH?

–571.6 kJ?

100

If a reaction goes from solid reactants to gaseous products, the entropy change ΔS is usually this sign.

+

100

This symbol represents specific heat capacity in the formula q=mcΔTq = m c \Delta Tq=mcΔT

c

200

What is ΔE and how do you find it?

change in internal energy of a system; ΔE = q + w

200

What must ΔH and ΔS be when something is freezing?  Is this spontaneous?

-, -, spontaneous at low temperature

200

When using Hess’s Law, if you multiply a reaction by 2, you must also multiply this by 2.

enthalpy change (ΔH)

200

The Second Law of Thermodynamics states that for a spontaneous process, the total entropy of the universe must do this.

ΔS > 0

200

A 50 g metal sample is heated from 25°C to 75°C. If it absorbs 10,000 J of heat, the specific heat capacity c is calculated using this formula.

c = q / (m ΔT) = 10,000 ÷ (50 × 50) = 4.0 J/g·°C?

300

What equation is derived from the 2nd law of thermodynamics regarding entropy at equillibrium?

ΔS = q/T

300

What must ΔH and ΔS be when something is melting?  Is this spontaneous?

+, +, spontaneous at high temperature

300

If

C(s)+O2(g)→CO2(g)  ΔH=−393.5 

and

C(s)+1/2 O2(g)→CO(g)  ΔH=−110.5 

find ΔH for

CO(g)+1/2 O2(g)→CO2(g)

–283.0 kJ? (–393.5 – (–110.5))

300

1 mole of ice melts at 0°C (273 K). The heat of fusion is 6.01 kJ/mol.
Calculate the entropy change ΔS for the melting.

22.0 J/K

300

A 100 g piece of copper (c = 0.385 J/g·°C) is heated from 25°C to 75°C. How much heat is absorbed?

q = 100 × 0.385 × (75–25) = 1,925 J?

400

What equation do you use for work done by or on a gas?  What do all variables stand for and their units?

w = -P ΔV

w = work in joules

P = external pressure in atm or Pa

ΔV = change in volume usually in liters

400

What must ΔH and ΔS be in non-natural endothermic reactions?  Is this spontaneous?

+, -, never spontaneous

400

Use Hess’s Law to find ΔH for:

C(s)+2H2(g)→CH4(g)

Given:
1️⃣ C(s)+O2(g)→CO2(g)  ΔH = –393.5 kJ
2️⃣ H2(g)+12O2(g)→H2O(l) ΔH = -285.8 kJ
3️⃣ CH4(g)+2O2(g)→CO2(g)+2H2O(l)  ΔH = –890.3 kJ

–74.9 kJ
(By reversing Reaction 3 and combining with 1 and 2)

400

1 mole of water vaporizes at 100°C (373 K). The heat of vaporization is 40.7 kJ/mol.
Calculate ΔS for the phase change.

109 J/K

400

A gas absorbs 400 J of heat and 100 J of work is done on it. What is ΔE for the system?

ΔE = q + w = 400 + 100 = 500 J?

500

What does the 1st law of thermodynamics say?  What equation is symbolic of this? 

Energy cannot be created or destroyed, it can only be transferred or transformed.

ΔE=q+w

500

This thermodynamic quantity determines spontaneity when both enthalpy and entropy are known.

Gibbs free energy (ΔG)

500

Find ΔH for

2NO(g)+O2(g)→2NO2(g)

Given:
1️⃣ N2(g)+O2(g)→2NO(g)  ΔH = +180 kJ
2️⃣ N2(g)+2O2(g)→2NO2(g) ΔH = +66 kJ


–114 kJ
(ΔH = 66 – 180)

500

A reaction absorbs 15 kJ of heat reversibly at 298 K.
Calculate the entropy change ΔS of the system.

50.3 J/K

500

A gas expands against a pressure of 2 atm from 3 L to 8 L. Calculate the work done (w) in J. (1 L·atm = 101.3 J)

w = –PΔV = –2(8–3) = –10 L·atm = –1,013 J?

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