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100
Given a 60W lightbulb at 120 volts

a) What is the resistance of the lightbulb while it's on?

b) Calculate how many kWh the lightbulb uses in 1 hour.


a) 240 ohms

R = V^2 / P 

(120)^2/60

b) .060kWh

E = P*t = (60W)(1Hr) / 1000

100

A battery with internal resistance is connected to a load resistance. If it is increased, does the terminal voltage of the battery increase, decrease, or stay the same?  

 The voltage of the real battery increases

(It has a smaller drop off)

Vbat = Remf/(R+rin)

100

A capacitor is discharged through a 100-ohm resistor. The discharge current decreases to 25% of its initial value in 2.5 ms. What is the value of the capacitor?

C = 18uF

200


Rank in order from largest to smallest, the powers of each resistor

PC >PD>PA >PB

200

Rank the Resistors Resistance

IC > IA = ID >IB

200

What value resistor will discharge a 1.0uF capacitor to 10% of its initial charge in 2.0 ms?

R= .87kila-omhs

300

A)What is the resistance of a 1500W (120V) hair dryer?
B)What is the current in the hair dryer when it is used?

A) 9.60omhs
R=(v)^2/P

B)12.5A
I = V/R

300

For the circuit shown, find the current through and the potential difference across each resistor.

Table

R     V     A

3     6     2

4     4     1

6     4    .67  

7     14     2

12    4    .33

300

 The switch has been closed for a very long time.

  1. What is the charge on the capacitor?

  2. The switch is opened at t=0s. At what time has the charge on the capacitor decreased to 10% of its initial value?

1. Q=VC -> 80uC

2. .23ms

ln(.10)= -t/(50)(2.0uf)

400

A car’s starter motor consumes 3.8 kW of electric power.

a) How much current does the motor draw from the 12 V car battery?

b) How much charge is delivered to the motor in the 2.0 s it takes to start?

A) 3.2*10^2 A

I = P/V

B) 6.38*10^2 C

q = I*time

400

Find the current through and potential difference across each resistor for the circuit shown. Place your results in a table for ease of reading.

 

table

5     8     1.6

10     16    1.6

6     14.4   2.4

4      9.6   2.4


400

A  150uF defibrillator capacitor is charged to 1500 V. When fired through a patient’s chest, it loses 95% of its charge in 40 ms. What is the resistance of the patient’s chest?

89 omhs

0.050= e-t/rc

solve r

500

What power is dissipated by the 2-ohm resistor?


W= 1.1W


Loop Law 

I3 = .75A

P= I2R

500

What is the current through the 10-ohm resistor? Is the current from left to right or right to left?

 

I = .36A

left to right 

500

You’ve made the finals of the Science Olympics! As one of your tasks, you’re given 1.0 g of aluminum and asked to make a wire, using all the aluminum, that will dissipate 7.5 W when connected to a 1.5 V battery. The density of aluminum is 1.0*10-3kg. What length and diameter will you choose for your wire?

r = .243mm

L =2.0m

Work

P=V^2/R => R

R = pL/A => L =(3.366*10^7m^-1) * r^2

Density / Volume => 1.0*10^-3 / pi * r^2 * L = r^2*L = 1,179*10^-7

system of equations

L= 2.0m,r =.243mm


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