single term
g(x)=3245
g'(x)=0
f(x)=sin(x)
f'(x)=cos(x)
y=x^2+4
y'=2x
y=3/x
y'=-3/x^2
f(x)=x^3cos(x)
f'(x)=x^2(3cos(x)-xsin(x))
x(t)=t
x'(t)=1
g(x)=cos(x)
g'(x)=-sin(x)
f(x)= 5x3+2x
f'(x)= 15x2+2
g(x)=1/x^2
g'(x)=-2/x^3
h(x)=(sinx)/(x^2)
h'(x)=(xcosx-2sinx)/x^3
y=x2
y'=2x
y=-cos(x)
y'=sin(x)
g(x)=-3x4+7x2
g'(x)=-12x3+14x
h(x)=x/2
h'(x)=1/2
g(x)=root(3)(6x^2+1
g'(x)=(4x)/((6x^2+1)^(2/3)
y=sqrtx
y'=1/(2sqrtx)
h(x)=tan(x)
h'(x)=sec2(x)
h(x)=6x^5-4root(3)x
h'(x)=30x^4-4/(3x^(2/3)
k(x)=1/sqrt(x)
k'(x)=-1/(2x^(3/2))
f(x)=1/4sin^2(2x)
f'(x)=sin(2x)cos(2x)
f(x)=root(3)(x^5)
f'(x)=5/3x^(2/3)
h(x) = cot(x)
h'(x)=-csc^2(x)
g(x)=sin(x)+cos(x)
g'(x)=cos(x)-sin(x)
g(x)=2/root(4)(x^3
g'(x)=3/(2x^(1/4))
find
f''(x)
given
f(x)=1/(11x-6)
f''(x)=242/(11x-6)^3