Power Rule/Sum/Difference
Product/Quotient
Higher Order
Chain Rule
Final Jeopardy
100

f' of f(x) = -4x5

-20x4

100

f' of f(x) = (3x2)/(x5/2)

(-3)/(2x3/2)

100

f'' of f(x) = 3x3

18x

100

f' of f(x)=sin(6x)

6cos(6x)

100

Whenever You Are Ready!

Prove the Quotient Rule by using the Chain Rule

200

f' of f(x) = x+ 4x + 2

2x + 4

200

f' of f(x) = x3(1 - 2x2)

x2(3 - 10x2)

200

f'' of f(x) = 2x- 4x + 6

4

200

f' o f(x) = (x- 1)3

6x(x- 1)2

300

f' of f(x) = (2/3)x4 - 3x2

(8/3)x3 - 6x

300

f' of f(x) = (3x2)/(1 - 2x)

[6x(1 - 3x)]/[(1 - 2x)2]

300

a(t) of s(t) = -4.9t+ 13t + 27

-9.8

300

f' of f(x) = cos2(x- 4)

-4x cos(x- 4)sin(x- 4)

400

f' of f(x) = (4x2 - 3x)/5

(8x - 3)/5

400

f' of f(x) = (4x2)/(1 - x7/3)

[4x(6 + x7/3)]/[3(1 -  x7/3)2]

400

f'' of f(x) = g(x)h(x)

g(x)h''(x) + 2g'(x)h'(x) + h(x)g''(x)

400

f' of f(x) = (4 - x4)-1/2

2x3(4 - x4)-3/2

500

f' of f(x) =axb + x(c - d)3

abxb-1 + (c - d)3

500

f' of f(x) = (1 + x)3/2(x4)

[x3(1 + x)1/2(11x + 8)]/2

500

g''' of g(x) =(1 - x)4

-24(1-x)

500

g" of g(x) = sin2(4x)

Preferred: 32cos 8x

Equivalent: 32(cos24x - sin24x)

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