f' of f(x) = -4x5
-20x4
f' of f(x) = (3x2)/(x5/2)
(-3)/(2x3/2)
f'' of f(x) = 3x3
18x
f' of f(x)=sin(6x)
6cos(6x)
Whenever You Are Ready!
Prove the Quotient Rule by using the Chain Rule
f' of f(x) = x2 + 4x + 2
2x + 4
f' of f(x) = x3(1 - 2x2)
x2(3 - 10x2)
f'' of f(x) = 2x2 - 4x + 6
4
f' o f(x) = (x2 - 1)3
6x(x2 - 1)2
f' of f(x) = (2/3)x4 - 3x2
(8/3)x3 - 6x
f' of f(x) = (3x2)/(1 - 2x)
[6x(1 - 3x)]/[(1 - 2x)2]
a(t) of s(t) = -4.9t2 + 13t + 27
-9.8
f' of f(x) = cos2(x2 - 4)
-4x cos(x2 - 4)sin(x2 - 4)
f' of f(x) = (4x2 - 3x)/5
(8x - 3)/5
f' of f(x) = (4x2)/(1 - x7/3)
[4x(6 + x7/3)]/[3(1 - x7/3)2]
f'' of f(x) = g(x)h(x)
g(x)h''(x) + 2g'(x)h'(x) + h(x)g''(x)
f' of f(x) = (4 - x4)-1/2
2x3(4 - x4)-3/2
f' of f(x) =axb + x(c - d)3
abxb-1 + (c - d)3
f' of f(x) = (1 + x)3/2(x4)
[x3(1 + x)1/2(11x + 8)]/2
g''' of g(x) =(1 - x)4
-24(1-x)
g" of g(x) = sin2(4x)
Preferred: 32cos 8x
Equivalent: 32(cos24x - sin24x)