Distributive Property
Combining Like Terms
Factoring (Stealing)
Changing a Number to Distributive
What's the solution?
100

4(x+2)

4x + 8

100

3x + 4 + 2x

5x + 4

100

Divide out a common factor to change 4 + 6 into the distributive property (a product and a sum).

2 (2 + 3)

100

Change 10 to a product and a sum of two numbers

Example: 2 (3 + 2)
100

Is x=2 a solution for x + 1 = 3

Yes

200

5(x - 12)

5x - 60

200
8a + 15a + a + 9
What is 24a + 9
200

Divide out a common factor to change 12 + 15 into the distributive property (a product and a sum).

3 (4 + 5)

200

Change 15 to a product and a sum of two numbers

Example: 3 (1 + 4)

200

{2, 3, 4}  when x - 2 = 1

3 is the solution

300

6 (5p + 10 - 2p)

18p + 60

300

21b - 11b - 10 - 9b

What is b - 10

300

Divide out a common factor to change 64 + 32 into the distributive property (a product and a sum).

8 (8 + 4)

300

Change 50 to a product and a sum of two numbers

Example: 5 (5 + 5)

300

{8, 9, 10}  when 5x = 50

10 is the solution
400

11 (10 + 8e - 2y - 2e)

110 + 66e -22y

400
12t + 8(2t + 4)
What is 28t + 32
400

Divide out a common factor to change 82 + 41 into the distributive property (a product and a sum).

41 (2 + 1)

400

Change 72 to a product and a sum of two numbers

Example: 9 (4 + 4)

400

{4, 8, 12} when 2y + y = 24

The solution is 8
500

25 (4f - 2f + 10 - 6 + f - 1 + 1 + f)

100f + 100

500
m + 5(4n + 5m) + 6n
What is 26m + 26n
500

Divide out a common factor to change 155 + 75 into the distributive property (a product and a sum).

Example: 5 (31 + 15)

500

Change 156 to a product and a sum of two numbers

Example: 13 (11 + 1)

500

{2, 4, 6, 8} when 9y + 10 - 5y - 2 - y + 12 +7y = 100

8 is the solution

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