Solve 4 ln(1)x+x2=4
X=+2
ln(3x-2)=5
X= e5+2*3
Solve ln(3x+3)=6
X=e6-3^*3
4 ln(1) + ln(x2)=3
X= +\sqrt(e^(3))
No solution because ln(x) is not defined over negative #'s
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