In the equation for an ellipse, what does the (h,k) stand for?
CENTER
The "a" value of an ellipse represents the distance from the center to a __________
VERTEX
The "b" value in an ellipse represents the distance from the center to a ______
CO-VERTEX
The "c" value of an ellipse represents the distance from the center to a ________
FOCUS
In an ellipse, 2a is the length of the ________ axis.
major
If the b squared is under the y squared in the formula for an ellipse, then the ellipse is ________
HORIZONTAL
True or False:
The a value is always larger than the b value for an ellipse.
TRUE
True or False:
The c value can sometimes be larger than the a value for an ellipse.
FALSE
True or False:
To find the vertices in a horizontal ellipse, you take half the "a" squared value and count that many spaces to the right and left of the center.
FALSE
How do you find the c-value if you know the a and b values for an ellipse?
c2 = a2 - b2
Find the vertices of a vertical ellipse centered at the origin with a = 7.
The vertices are (0, 7) and (0, -7).
Find the co-vertices of a horizontal ellipse centered at (0,0) with b = 2.
The co-vertices are (0, 2) and (0, -2).
Find the foci of a horizontal ellipse centered at (0,0) with c = 4.
The foci are (-4,0) and (4,0).
What is the center of the ellipse given the equation
(x+1)2 /9 + (y-3)2/25 = 1
The center is (-1,3).
Find the distance from the center to the focus given the equation (x - 3)2 / 49 + (y + 2)2 / 9 = 1 .
c = 2 square root of 10
If a vertex of an ellipse centered at the origin is located at (0,5) and a co-vertex is located at (4,0), then give the coordinates of the foci of the ellipse.
The foci are (0,3) or (0, -3).
Write the equation of an ellipse centered at (0,0) with a vertex at (10,0) and a co-vertex at (0,-3).
x2 / 100 + y2 / 9 = 1
Find the vertices of the ellipse given
(x + 1) 2 / 4 + (y - 2)2 / 9 = 1 .
Vertices ( -1,5) and ( -1, -1)
Given (x - 5)2 / 25 + (y - 3)2 /4 = 1 find the
co-vertices.
(5,5) and (5,1)
What is the equation of the vertical ellipse given that its center is at (-2, -5), a=6, and b=3 ?
(x+2)2 /9 + (y+5)2 /36 = 1
Give the general form of this equation
x2 / 16 + y2 /9 = 1
9x2 + 16y2 = 144
Transform this equation to standard form:
x2 + 4y2 + 10x - 8y + 13 = 0
(x+5)2 /16 + (y-1)2 /4 = 1
Given 16x^2 + 9y^2 = 144, find the foci
(0, square root of 7) and (0, neg square root of 7)
Given the equation of the ellipse, find the center. 25x^2 + 16y^2 + 150x -160y = -225
(-3,5)
x2/ 25 + (y+2)2/9 = 1
9x2 + 25y2 + 100y - 125 = 0